In: Statistics and Probability
An elevator has a placard stating that the maximum capacity is 1610 lblong dash10 passengers. So, 10 adult male passengers can have a mean weight of up to 1610 divided by 10 equals 161 pounds. If the elevator is loaded with 10 adult male passengers, find the probability that it is overloaded because they have a mean weight greater than 161 lb. (Assume that weights of males are normally distributed with a mean of 171 lb and a standard deviation of 28 lb.) Does this elevator appear to be safe?
Solution :
mean = = 171
standard deviation = = 28
n = 10
= = 171
= / n = 28 / 10 = 8.85
P( > 161) = 1 - P( < 161)
= 1 - P[( - ) / < (161 - 171) / 8.85]
= 1 - P(z < -1.13)
Using z table,
= 1 - 0.1292
= 0.8708
No,there is good chance that 10 randomly selected people will exceed the elevator capacity