For the following pairs which has the higher entropy (a) 1 mole of gaseous heptane and...

For the following pairs which has the higher entropy

(a) 1 mole of gaseous heptane and 1 mole liquid heptane (both at 50oC)

(b) 1 mole of liquid ethanol at 20oC and 1 mole of liquid ethanol at 40oC

(c) 1 mole of oxygen (O2) gas and 1 mole of ozone gas (O3) (both at 25oC)

(d) 1 mole of hydrogen gas in 20 L and 1 mole of hydrogen gas in 10 L (both at 0oC)

Expert Solution

Entropy is the degree of disorderness.

The disorderness will increases in the order is : solids < liquids < gases

(a) 1 mole of gaseous heptane and 1 mole liquid heptane (both at 50oC)

So 1 mole of gaseous heptane has higher entropy than 1 mole liquid heptane.

(b) 1 mole of liquid ethanol at 20oC and 1 mole of liquid ethanol at 40oC

As the temperature increases the disorderness increases so 1 mole of liquid ethanol has less entrropy than 1 mole of liquid ethanol at 40oC.

(c) 1 mole of oxygen (O2) gas and 1 mole of ozone gas (O3) (both at 25oC)

since the molar mass of O3 is more than that of O2 so the disorderness will be more in O2

Therefore 1 mole of oxygen (O2) gas has more than that of 1 mole of ozone gas (O3)

(d) 1 mole of hydrogen gas in 20 L and 1 mole of hydrogen gas in 10 L (both at 0oC)

Since the volume is more the molecules are free to more so the entropy will be more in1 mole of hydrogen gas in 20 L

queen_honey_blossom answered 2 years ago

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