In: Statistics and Probability
Given the following data that was sampled from a normal population distribution: 1257 1306 1250 1292 1268 1316 1275 1317 1275
Determine a 95% confidence interval for the population mean. (round to nearest integer)
lower limit
upper limit
Let x be the given data values.
n = 9
Sample mean :
x | |
1257 | 729 |
1306 | 484 |
1250 | 1156 |
1292 | 64 |
1268 | 256 |
1316 | 1024 |
1275 | 81 |
1317 | 1089 |
1275 | 81 |
Sample standard deviation :
s = 24.9098 (Round to 4 decimal)
Here population standard deviation is not known so we use t interval.
Confidence level = c = 0.95
degrees of freedom = n - 1 = 9 - 1 = 8
t critical value = tc = 2.306 (From statistical table of t values)
Lower limit :
LL = 1264.853
LL = 1265 (Round to nearest integer)
Upper limit :
UL = 1303.147
UL = 1303 (Round to nearest integer)
Lower limit = 1265
Upper limit = 1303
95% Confidence interval for population mean is (1265, 1303)