Use the standard normal distribution or the? t-distribution to
construct a 90 confidence interval for the population mean. Justify
your decision. If neither distribution can be? used, explain why.
Interpret the results. In a recent? season, the population standard
deviation of the yards per carry for all running backs was 1.37.
The yards per carry of 25 randomly selected running backs are shown
below. Assume the yards per carry are normally distributed.
2.4 4.5 3.6 5.3 4.8 6.8 5.9 4.9...
Consider a normal population distribution with the value of \(\sigma\) known.(a) What is the confidence level for the interval \(\bar{x} \pm 2.88 \sigma / \sqrt{n} ?\) (Round your answer to one decimal place.)\(\%\)(b) What is the confidence level for the interval \(\bar{x} \pm 1.47 \sigma / \sqrt{n} ?\) (Round your answer to one decimal place.) \(\%\)(c) What value of \(z_{\alpha / 2}\) in the CI formula below results in a confidence level of \(99.7 \% ?\) (Round your answer to...
Assuming that the population is normally distributed, construct
a 90 % confidence interval for the population mean, based on the
following sample size of n equals 5. 1, 2, 3, 4, and 29 In the
given data, replace the value 29 with 5 and recalculate the
confidence interval. Using these results, describe the effect of
an outlier (that is, an extreme value) on the confidence
interval, in general.
7.A random sample of 49 observations is drawn from a population
with a normal distribution. If the sample mean is 265 and the
sample standard deviation is 57, find the 95% confidence interval
for the population mean.
8. A random sample of 49 observations is drawn from a population
with a normal distribution with a standard deviation of 57. If the
sample mean is 265, find the 95% confidence interval for the
population mean. Compare this confidence interval with the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ
from the following data. State the point estimate. Assume the data
come from a normally distributed population. 12.9 11.6 11.9 12.2
12.5 11.4 12.0 11.7 11.8 12.9
(Round the intermediate values to 4 decimal places. Round your
answers to 2 decimal places.)
90% confidence interval: ?≤ μ ?≤
95% confidence interval: ?≤ μ? ≤
99% confidence interval:? ≤ μ ?≤
The point estimate is?
Construct 90%, 95%, and 99% confidence intervals to estimate
μ from the following data. State the point estimate.
Assume the data come from a normally distributed
population.
13.2
11.6
11.9
12.5
12.5
11.4
12.0
11.7
11.8
13.2
Appendix A Statistical Tables
(Round the intermediate values to 4 decimal places.
Round your answers to 2 decimal places.)
90% confidence interval: enter the lower limit of the 90%
confidence interval ≤ μ ≤ enter the upper limit
of the 90% confidence interval
95%...
Construct 90%, 95%, and 99% confidence intervals to estimate
μ from the following data. State the point estimate.
Assume the data come from a normally distributed
population.
11.9
11.6
11.9
13.0
12.5
11.4
12.0
11.7
11.8
11.9
Appendix A Statistical Tables
(Round the intermediate values to 4 decimal places.
Round your answers to 2 decimal places.)
90% confidence interval: enter the lower limit of the 90%
confidence interval ≤ μ ≤ enter the upper limit
of the 90% confidence interval
95%...