Question

Given a normal distribution with mean population of 51 and standard devitation of 8​, and given you select a sample of n=100​, complete parts​ (c).

c. What is the probability that X(w/ bar above) is above 51.6​? ​(Type an integer or decimal rounded to four decimal places as​ needed.)

Answer 1

Solution:

Given that,

mean = = 51

standard deviation = = 8

n = 100

= 51

=  ( /n) = (8/ 100 ) =0.8

p (   > 51.6 )

1 - p (   < 51.6 )

1 -p ( - /) < (51.6 - 51 / 0.8)

1 - p ( z < 0.6 / 0.8 )

1 - p ( z < 0.75)

Using z table

=1 - 0.7734

= 0.2266

Probability = 0.2266,