Which ONE of the following represents the CORRECT equilibrium constant expression for the reaction: H2PO4 ¯...

Which ONE of the following represents the CORRECT equilibrium constant expression for the reaction:

H2PO4 ¯ + OH¯ ⇔ HPO4^2-+ H2O

(a) 1/k_b(b) 1/k_a (c) k_w/k_a(d) k_w/k_b(e) k_b/k_w

Solutions

Expert Solution

Correct option = (a)1/ K_b

Given,

H₂PO₄^- + OH^- HPO₄^2-+ H₂O

K_eq = ([HPO₄^2-][H₂O])/([H₂PO₄^- ][OH^-])

= [HPO₄^2-]/([H₂PO₄^- ][OH^-]) ([H2O] =1 as it is a pure liquid)

Now consuder the following equilibrium reaction,

HPO₄^2-+ H₂O H₂PO₄^- + OH^-

In this case,

Equilibrium constant = Base dissociation constant (K_b)

equilibrium constant = K_b = ([H₂PO₄^- ][OH^-])/[HPO₄^2-]

or K_b = 1/ K_eq ( K_eq = [HPO₄^2-]/([H₂PO₄^- ][OH^-])

or, K_eq = 1/ K_b

Therefore correct equilibrium constant expression = option (a) = 1/ K_b

queen_honey_blossom answered 1 year ago

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