Add 10 mL of 0.1 M HCl to one liter of a 0.10 M sodium acetate...

Add 10 mL of 0.1 M HCl to one liter of a 0.10 M sodium acetate buffer, pH 6.76 (pKa = 4.76 for acetic acid). Does the pH of the solution change? Determine the effect of the addition of 20.0 mL of 0.100 M HCl?

Expert Solution

moles of acetate = 1L * 0.10mol/L = 0.10mol
moles of acetic acid = 0.10 mol
H⁺ + CH₃COO^- <---------> CH₃COOH
moles of acetate after adding 10mL of 0.1M HCl = 0.10 - 1*10^-3 = 0.099mol
moles of acetic acid after adding HCl= 0.1+ 1*10^-3 = 0.101 mol
PH = Pka + log [acetate/acetic acid]
PH = 4.76 + log [0.099/0.101] = 4.75
Therefore the PH changes after adding 10mL of 0.1M HCl to 1L of buffer
Similarly you can do it for 20mL adition,
moles of acetate after adding 20mL = 0.1 - 2*10^-3 = 0.098 mol
moles of acetic acid after adding HCl = 0.1 + 2*10^-3 = 0.102 mol
PH = 4.76 + log [0.098/0.102] = 4.74

queen_honey_blossom answered 2 years ago

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