Question

*Calculate the mass of sodium acetate (CH3COONa) required to prepare 50 mL of a 0.10 M sodium acetate solution. Show work. Verify that this matches the amount you place into cup #3 in Activity 1.

*Calculate the volume of 6 M acetic acid needed to prepare 100 mL of a 0.10 M acetic acid (CH3COOH) solution. Show work.

*Calculate the volume of 1 M sodium hydroxide (NaOH) needed to prepare 10 mL of a 0.10 M sodium hydroxide solution. Show work.

*Calculate the volume of 1 M hydrochloric acid (HCl) needed to prepare 10 mL of a 0.10 M hydrochloric acid solution. Show work.

*Write a balanced equation for the dissociation reaction of acetic acid in water.

Answer 1

A) molar mass of sodium acetate =82.02 gm/mol

calculate number of mol

given 50ml solution of 0.10 M

=50 x 0.10 / 1000 = 0.005 mol required for 0.10M 50 ml Na acetate solution

calculate mass by multiplying molar mass of Na acetate

Mass of sodium acetate = num of mole x molar mass = 0.005 x 82.02 = 0.4101 gm

Mass of sodium acetate = 0.4101 gm

B) Calculate the volume of 6 M acetic acid needed to prepare 100 mL of a 0.10 M acetic acid (CH3COOH) solution

Given M₁= 6M ,V₁= ? M₂ =0.10M & V₂=100 ml

Formula

M₁V₁= M₂ V₂ i.e. = 6 x V₁ = 100 x 0.10 V₁ = 1.6667 ml

V₁ = 1.7 ml acetic acid needed to prepare 100 mL of a 0.10 M acetic acid solution.

c) Calculate the volume of 1 M sodium hydroxide (NaOH) needed to prepare 10 mL of a 0.10 M sodium hydroxide solution

Given M₁= 1 M ,V₁= ? M₂ =0.10M & V₂=10 ml

Formula

M₁V₁= M₂ V₂ i.e. = 1 x V₁ = 10 x 0.10 V₁ = 1 ml

V₁ = 1 ml sodium hydroxide (NaOH) needed to prepare 10 mL of a 0.10 M sodium hydroxide solution.

D) *Calculate the volume of 1 M hydrochloric acid (HCl) needed to prepare 10 mL of a 0.10 M hydrochloric acid solution.

Given M₁= 1 M ,V₁= ? M₂ =0.10M & V₂=10 ml

Formula

M₁V₁= M₂ V₂ i.e. = 1 x V₁ = 10 x 0.10 V₁ = 1 ml

V₁ = 1 ml hydrochloric acid (HCl) needed to prepare 10 mL of a 0.10 M hydrochloric acid solution.

E) Write a balanced equation for the dissociation reaction of acetic acid in water.

balnce equation is

CH3COOH + H2O CH3COO- + H3O+