A 100. ml sample of 0.10 M HCl is mixed with 50. ml of 0.10 M...

A 100. ml sample of 0.10 M HCl is mixed with 50. ml of 0.10 M NH₃. What is the resulting pH?

Thank you!

Expert Solution

no of moles of HCl = molarity * volume in L

= 0.1*0.1 = 0.01 moles

no of moles of NH3 = 0.1*0.05 = 0.005moles

HCl + NH3 ---------> NH4Cl

I 0.01 0.005 0

c -0.005 -0.005 0.005

E 0.005 0 0.005

[H+] = no of moles of Hcl at equilibrium /total volume in L

= 0.005/0.15 = 0.0333M

PH = -log[H+]

= -log0.0333 = 1.4775

queen_honey_blossom answered 1 year ago

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