You add 300 mL of Tris-HCl at 0.1 M to a 0.2 L solution of 0.9%...

You add 300 mL of Tris-HCl at 0.1 M to a 0.2 L solution of 0.9% (w/v)NaCl, and to which you add 500 mg of NaCl (powder).
What is the concentration of Tris-HCl in mM and in g/L?
Tris-HCl : MW 121.14
NaCl : MW 58.44

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Expert Solution

30p mL solution of Tris HcL molarity is = 0.1 M.

Then we have added this solution to 0.2 L solution or 200 mL of 0.9 % Nacl.

So final volume is 200+ 300= 500mL.

Answer has been attached below as image.

gladiator answered 1 year ago

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