In: Statistics and Probability
1. Music seems to be everywhere in society, and psychologists have investigated its effects on a variety of performances. For example, suppose an experimenter created three equivalent groups of eight people each and asked each person to perform a proofreading task on a short research paper. Subjects in group A1 performed the task with no music playing in the background, subjects in group A2 performed the task with a selection of oldies playing in the background, and subjects in groups A3 performed the task while listening to hard rock. The dependent variable was the errors detected out of a possible 50. Suppose the following scores were obtained:
No Music (A1) |
Oldies (A2) |
Hard Rock (A3) |
40 |
34 |
26 |
41 |
39 |
24 |
39 |
38 |
19 |
36 |
40 |
23 |
35 |
34 |
18 |
32 |
35 |
21 |
31 |
29 |
23 |
34 |
36 |
29 |
1.a.Analyze the scores with a one-factor between-subjects ANOVA to answer the question: Did the music condition affect the number of errors detected by a subject? Use α= .05. If needed, use the Tukey HSD test for multiple (pairwise) comparisons.
1.b.Report the results of this experiment as it would appear in a research paper.
1.a.Analyze the scores with a one-factor between-subjects ANOVA to answer the question: Did the music condition affect the number of errors detected by a subject? Use α= .05. If needed, use the Tukey HSD test for multiple (pairwise) comparisons.
MINITAB used
One-way ANOVA: No Music, Oldies, Hard Rock
Method
Null hypothesis |
All means are equal |
Alternative hypothesis |
Not all means are equal |
Significance level |
α = 0.05 |
Equal variances were assumed for the analysis.
Factor Information
Factor |
Levels |
Values |
Factor |
3 |
No Music, Oldies, Hard Rock |
Analysis of Variance
Source |
DF |
Adj SS |
Adj MS |
F-Value |
P-Value |
Factor |
2 |
893.3 |
446.63 |
34.39 |
0.000 |
Error |
21 |
272.8 |
12.99 |
||
Total |
23 |
1166.0 |
Model Summary
S |
R-sq |
R-sq(adj) |
R-sq(pred) |
3.60390 |
76.61% |
74.38% |
69.45% |
Means
Factor |
N |
Mean |
StDev |
95% CI |
No Music |
8 |
36.00 |
3.70 |
(33.35, 38.65) |
Oldies |
8 |
35.63 |
3.50 |
(32.98, 38.27) |
Hard Rock |
8 |
22.88 |
3.60 |
(20.23, 25.52) |
Pooled StDev = 3.60390
Tukey Pairwise Comparisons
Grouping Information Using the Tukey Method and 95% Confidence
Factor |
N |
Mean |
Grouping |
|
No Music |
8 |
36.00 |
A |
|
Oldies |
8 |
35.63 |
A |
|
Hard Rock |
8 |
22.88 |
B |
Means that do not share a letter are significantly different.
Tukey Simultaneous Tests for Differences of Means
Difference of Levels |
Difference |
SE of |
95% CI |
T-Value |
Adjusted |
Oldies - No Music |
-0.38 |
1.80 |
(-4.91, 4.16) |
-0.21 |
0.976 |
Hard Rock - No Music |
-13.13 |
1.80 |
(-17.66, -8.59) |
-7.28 |
0.000 |
Hard Rock - Oldies |
-12.75 |
1.80 |
(-17.29, -8.21) |
-7.08 |
0.000 |
Individual confidence level = 98.00%
1.b.Report the results of this experiment as it would appear in a research paper.
The 8 participants in the No Music group had an average number of error of 36.0 (SD = 3.7); the 8 participants in the Oldies group had an average error of 35.6 (SD = 3.5), and the 8 participants in the Hard Rock group had a mean of 22.9 (SD = 3.6). The effect of music therefore, was highly significant, F(2,21) = 34.4, p<.001.
Post hoc comparisons using the Tukey HSD test indicated that the mean error for the Hard Rock was significantly different than the No music and Oldies . However, the Oldies did not significantly differ from the No music conditions.