In: Statistics and Probability
A study is to be conducted to see how long it takes for a taxpayer to complete his income tax return. Assume that the time required to complete the return is normally distributed. A random sample of 17 taxpayers is taken whose mean (of the time in hours to complete the return) is 7.8 hours with a standard deviation of 2.3 hours. A) Determine the value of t B) Find the approximate error C) Find the interval with 95% confidence for the true mean of the time required to complete the tax return. All work must appear to receive credit
Solution :
Given that,
= 7.8
s =2.3
n =17
Degrees of freedom = df = n - 1 =17 - 1 = 16
a ) At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2= 0.05 / 2 = 0.025
t /2,df = t0.025,16 = 2.120 ( using student t table)
Margin of error = E = t/2,df * (s /n)
= 2.120* ( 2.3/ 17)
= 1.1826
The 95% confidence interval estimate of the population mean is,
- E < < + E
7.8 - 1.1826< < 7.8+ 1.1826
6.6174 < < 8.9826
( 6.6174 , 8.9826)