In: Statistics and Probability
The variable x is normally distributed with a mean of 500 and a standard deviation of 50. Find a) The 60th percentile. b)The 35th percentile. c)The x value which exceeds 80% of all x values. d)The x value that is exceeded by 80% of all x values.
The answers are:
S.NO | Value | Condition |
a) | 512.667355 | 60th percentile |
b) | 480.733977 | 35th percentile |
c) | 542.081062 | x value which exceeds 80% |
d) | 457.918938 | x value that is exceeded by 80% of all x values. |
a)
We need to find x such that P(X≤x) = 0.60
Pr(X≤x)=Pr(Z≤(x−500)/50)=0.60
(x−500)/50 = 0.2533
> x = 512.667355
The following is obtained graphically:
b)
We need to find x such that P(X≤x) = 0.35
Pr(X≤x)=Pr(Z≤(x−500)/50)=0.35
(x−500)/50 = −0.3853
>x=480.733977
The following is obtained graphically:
c)
We need to find x such that P(X≤x) = 0.80
Pr(X≤x)=Pr(Z≤(x−500)/50)=0.80
(x−500)/50 = 0.8416
>x=542.081062
The following is obtained graphically:
d)
We need to find x such that P(X≤x) = 0.20
Pr(X≤x)=Pr(Z≤(x−500)/50)=0.20
(x−500)/50 = −0.8416
>x=457.918938
The following is obtained graphically:
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