Question
In: Statistics and Probability
The random variable x is normally distributed with a mean of 68 and a standard deviation...
The random variable x is normally distributed with a mean of 68 and a standard deviation of 4. Find the interquartile range (IQR)? Use R.
Solutions
Expert Solution
========================================CODE======================================
# First to find out Third Quartile with mean 68 and Standard deviation 4
Q3=qnorm(p = 0.75 ,mean = 68 ,sd =
4) # Third Quartile
Q3
Q1=qnorm(p = 0.25 ,mean = 68 ,sd = 4) # First
Quartile
Q1
IQR =Q3
-Q1
# Inter quartile range
IQR
======================================OUTPUT========================================
> Q3=qnorm(p = 0.75 ,mean = 68 ,sd = 4) # Third
Quartile
> Q3
[1] 70.69796
>
> Q1=qnorm(p = 0.25 ,mean = 68 ,sd = 4) # First Quartile
> Q1
[1] 65.30204
>
> IQR =Q3
-Q1
# Inter quartile range
> IQR
[1] 5.395918
orchestra answered 1 year agoRelated Solutions
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