Suppose a random variable X is normally distributed with mean 65.9 and standard deviation 9.5. Answer...

Suppose a random variable X is normally distributed with mean 65.9 and standard deviation 9.5. Answer the following questions:

P(42.15 < X < 77.30) = [round to 4 decimal places]

Tries 0/5

P(X ≤ 73.50) = [round to 4 decimal places]

Tries 0/5

P(X = 77.30) = [round to 4 decimal places]

Tries 0/5

Suppose a is such that: P(X ≤ a) = 0.49. Then a = [round to 2 decimal places]

Tries 0/5

What is the IQR (inter-quartle range) of X? [round to 2 decimal places

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orchestra answered 1 year ago

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