In: Chemistry
SO3(g) can be produced by this two step process:
1.) 2FeS2 + 1 1/2 O2 = Fe2O3 + 4SO2
2.) SO2 + 1/2 O2 = So3
How many grams of SO3 can be produced from the reaction of 45.0 g of FeS2 if there is no experimental error? How many grams would actually be measured if reaction 1 had 100% yield and reaction 2 had 83.4% yield?
1)
2 FeS2 + 1 1/2 O2 -------------> Fe2O3 + 4 SO2
240 g 256.2 g
45.0 g ??
mass of SO2 produced = 45.0 x 256.2 / 240
= 48.1 g
SO2 + 1/2 O2 ------------> So3
64.06 g 80.06 g
48.06 g ??
mass of SO3 produced = 48.06 x 80.06 / 64.06
mass of SO3 produced = 60.1 g
% yield = actual / theoretical ) x 100
83.4 = Actual / 60.1 ) x 100
Actual yield = 50.1 g