In: Advanced Math
The rate at which the ice melts is proportional to the amount of ice at the instant. Find the amount of ice left after 2 hours if half the quantity melts in 30 minutes. Solution. Let m be the amount of ice at any time t.
∴dmdt=km⇒dmm=kdt∫dmm=k∫dt+C⇒logm=kt+C At t=0,m=M:logM=0+C⇒C=logM On putting the value of C, (1) becomes, logm=kt+logMm=M2 when t=12 hour logM2=k2+logM⟹logM2M=k2⟹log12=k2 or k=2log12 On putting the value of k in (2), we have logm=(2log12)t+logM On putting t=2 hours in (3), we have logm=4log12+logM⇒logmM=log(12)4 or mM=116 or m=M16 After 2 hours, amount of ice left \( \frac{m}{M}=\frac{1}{16} \)of the amount of ice at the beginning.
Therefore. \( \frac{m}{M}=16 \)