Question

Write a program that repeatedly generates a random integer in the range [1, 100], one integer at a time, and displays the generated numbers on the screen according to the following rules:

• If the second number generated is greater than the first number, they are displayed on the screen in the order of their input and while the next random number generated is greater than the previous one, the random number is displayed on the screen and the program continues. As soon as the number generated is less than or equal to the previous one, the program terminates. For example, if the first 6 random numbers generated are 1, 6, 34, 67, 88, and 12, the output of the program would be:

1

6

34

67

88

• If the second number generated is less than the first number, they are displayed on the screen in the order of their input and while the next random number generated is less than the previous one, the random number is displayed on the screen and the program continues. As soon as the number generated is greater than or equal to the previous one, the program terminates. For example, if the first 3 random numbers generated are 44, 32, and 32, the output of the program would be:

44

32

• If the second number generated is equal to the first number, the program terminates and no message is displayed on the screen.

Note: Attach your cpp file to this question.

Answer 1

Code:

#include<iostream>  // header file for input output operation
#include <ctime>    // for random number generation
using namespace std;

int main(){
        srand ( time(NULL) );   // setting srand to get random different number each time code is executed 
    
    int number, array[1000], flag= 0, count = 0, value = 0; // value variable is used to decide the series is increasing or decreasing
    while (flag != 1){  // while loop till flag is set to 1 (flag variable used to check the rules)
        number = rand()%100 + 1;    // generating the random number
        array[count] = number;  // assigning to array
        if(count == 0){ // checking if first number is already entered or not   
            count++;    // increasing the counter value
            continue;   // skiping all other statements
        }

        if(count == 1 && number == array[0]){   // checking if first number id equal to second number
                flag = 1;   // setting the flag
                continue;
                } // end of if
        else if( count == 1 && number < array[0]){
            value = -1; // seting the value -1 for decreasing series
        }
        else if( count == 1 && number > array[0]){
            value = 1;  // seting the value 1 for increasing series
        }
        
        else{
            if( count > 1 && value == -1 ){ // decreasing series
                if (number >= array[count -1]){ // checking if number is greater than or equal to last entered number
                    flag = 1; // setting the flag
                } // end of if
                if (flag == 1){
                    for (int i=0;i<count;i++)   // loop to print the array contant
                        cout << array[i] << endl; // printing element
                } // end of if
            }
            
            
            else if(count > 1 && value == 1){  // increasing series
                if (number <= array[count -1]){ // checking if number is less than or equal to last entered number
                    flag = 1; // setting the flag
                } // end of if
                if (flag == 1){ // if flag is set
                    for (int i=0;i<count;i++)   // loop to print the array contant
                        cout << array[i] << endl; // printing element
                } // end of if
            }
            
        }// end of else
    count++;
    
    } // end of while
    return 0;
}

Sample output:

* you need to run the code again and again repidly to get best result. to get these result I have to run too many times as again and again system is generating number like big,lower,big and lower,big,lower

Note: Please let me know if you have any doubt or there is any change required in the code.