Question

C++ DO not use arrays to write this program.

Write a program that repeatedly generates three random integers in the range [1, 100] and continues as follows:

• If the right-most digit of all the three integers is equal, the program displays them in ascending order on the screen and continues. If the generated integers have different right-most digits, they are not displayed and the program continues. The program terminates once the right-most digits of all the three random numbers are equal to 0. For example, assuming:
  • the first three random integers are: 98, 23, 48
  • the second three random integers are: 45, 5, 75
  • the third three random integers are: 4, 95, 33
  • the fourth three random integers are: 11, 61, 21
  • the fifth three random integers are: 100, 20, 40 ---------> The program terminates as all the three numbers end with 0

The output will be:

5, 45, 75

11, 21, 61

20, 40, 100

Please notice that all the numbers are not displayed at the end of the program. Every line is displayed in one iteration and the last line is displayed in the last iteration of your loop.

• If the very first set of numbers generated all end with zero, for example, the first three integers are: 50, 40, 10, after the program shows these three numbers in ascending order, it also displays: "... are your lucky numbers."

So, the output would be:

10, 40, 50 are your lucky numbers.

California College

Answer 1

Program:

#include <iostream>

using namespace std;

void sortNumbers(int num1, int num2, int num3) {
    if(num1<num2 && num1<num3 && num2>num3 )
    {
        cout << num1 << " " << num3 << " " << num2;
    }
    else if(num1<num2 && num1<num3 && num2<num3 ) 
    {
        cout << num1 << " " << num2 << " " << num3;
    }
    else if (num2<num1 && num2<num3 && num3>num1 ){
        cout << num2 << " " << num1 << " " << num3;
    }
    else if (num2<num1 && num2<num3 && num3<num1 ){
        cout << num2 << " " << num3 << " " << num1;
    }
    else if (num3<num1 && num3<num2 && num1>num2){
        cout << num3 << " " << num2 << " " << num1;
    }
    else if (num3<num1 && num3<num2 && num1<num2){
        cout << num3 << " " << num1 << " " << num2;
    }
}

int main()
{
    bool isCheck = true;
    while (isCheck) {
        // To get random numbers range of 1-100
        int num1 = (rand() % 100) + 1;
        int num2 = (rand() % 100) + 1;
        int num3 = (rand() % 100) + 1;
        // Will give the right most digit of the number
        int num1Rem = num1%10;
        int num2Rem = num2%10;
        int num3Rem = num3%10;
        // condition to check if the right most digits are 0 for all 3 numbers
        if (num1Rem == 0 && num2Rem == 0 && num3Rem == 0) {
            isCheck = false;
            // Sort the numbers in ascending order 
            sortNumbers(num1, num2, num3);
            cout << " are lucky numbers" << endl;
        }
        // Condition to check if the right most digits are same for all 3 numbers
        else if (num1Rem == num2Rem && num1Rem == num3Rem && num2Rem == num3Rem) {
            cout << "Random integers are: ";
            sortNumbers(num1, num2, num3);
            cout << endl;
        }
        
    }

    return 0;
}

Output: