In: Statistics and Probability
Do a two-sample test for equality of means assuming unequal
variances. Calculate the p-value using Excel.
(a-1) Comparison of GPA for randomly chosen
college juniors and seniors:
x¯1x¯1 = 4, s1 = .20, n1 =
15, x¯2x¯2 = 4.25, s2 = .30,
n2 = 15, α = .025, left-tailed
test.
(Negative values should be indicated by a minus sign. Round
down your d.f. answer to the nearest whole number and
other answers to 4 decimal places. Do not use "quick" rules for
degrees of freedom.)
d.f. | |
t-calculated | |
p-value | |
t-critical | |
(b-1) Comparison of average commute miles for
randomly chosen students at two community colleges:
x¯1x¯1 = 17, s1 = 5, n1 =
22, x¯2x¯2 = 21, s2 = 7, n2
= 19, α = .05, two-tailed test.
(Negative values should be indicated by a minus sign. Round
down your d.f. answer to the nearest whole number and
other answers to 4 decimal places. Do not use "quick" rules for
degrees of freedom.)
d.f. | |
t-calculated | |
p-value | |
t-critical | +/- |
(c-1) Comparison of credits at time of graduation
for randomly chosen accounting and economics students:
x¯1x¯1 = 141, s1 = 2.8, n1
= 12, x¯2x¯2 = 138, s2 = 2.7,
n2 = 17, α = .05, right-tailed
test.
(Negative values should be indicated by a minus sign. Round
down your d.f. answer to the nearest whole number and
other answers to 4 decimal places. Do not use "quick" rules for
degrees of freedom.)
d.f. | |
t-calculated | |
p-value | |
t-critical | |
ANSWER::
Part a-1)
DF = 24
Test Statistic :-
t = -2.6854
P - value = P ( t > 2.6854 ) = 0.0065
Critical value t(α, DF) = t( 0.025 , 24 ) = 2.0639
Part b-1)
DF = 32
Test Statistic :-
t = -2.0752
P - value = P ( t > 2.0752 ) = 0.0461
Critical value t(α/2, DF) = t(0.05 /2, 32 ) = ± 2.0369
Part c-1)
DF = 23
Test Statistic :-
t = 2.8839
P - value = P ( t > 2.8839 ) = 0.0042
Critical value t(α, DF) = t( 0.05 , 23 ) = 1.7139
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