Question

Independent Samples Test
		Levene's Test for Equality of Variances		t-test for Equality of Means
		F	Sig.	t	df	Sig. (2-tailed)
F1	Equal variances assumed	12,130	,151	-1,967	194	,052
	Equal variances not assumed			-2,010	184,290	,046

A researcher thinks that mean value for F1 of the male is bigger than that of female.  (mu1 female, mu2 male)

Write down the hypothesis, p- value and conclusion.

Answer 1

Solution:

Null hypothesis(H0) : µ1(female)=µ2(male) , there is not significant difference between mean value of F1 of female and male.

Alternative hypothesis(H1) : µ1(female )<µ2(male) , mean value of F1 of the male is bigger than that of female.

Now , from the above independent sample test table output.

We look for F1 (equal variance assumed)

Levene’s test for equality of variance P-value=0.151>0.05 this is not significant so, we conclude our result from the row Equal variances assumed .

Now , we have our results :

t = -1.967

df=194

P-value=0.052 > 0.05 this is not significant ,

This difference is not significant

Conclusion: we fail to reject null Hypothesis(H0) at 5% level of significance and conclude that there is not significant difference between mean value of F1 of female and male.

If in case Levene’s test for equality of variance P-value < 0.05 then we conclude our result from the row Equal variances not assumed .