Question

What volume (L) of 0.986 M hydrochloric acid solution neutralizes 91.4 mL of 0.196 M sodium hydroxide solution ?

What volume (L) of 0.288 M potassium hydroxide solution would just neutralize 35.7 mL of 0.279 M H₂SO₄ solution?

Write the balanced total ionic equation for the same reaction. Enter your answer as the sum of the coefficients.

For the reaction HI + Pb(NO₃)₂ → ,write the balanced formula equation. Enter your answer as the sum of the coefficients.

ALL MUST BE ANSWERED !

Answer 1

1)

Balanced chemical equation is:

NaOH + HCl ---> NaCl + H2O

Here:

M(NaOH)=0.196 M

M(HCl)=0.986 M

V(NaOH)=91.4 mL

According to balanced reaction:

1*number of mol of NaOH =1*number of mol of HCl

1*M(NaOH)*V(NaOH) =1*M(HCl)*V(HCl)

1*0.196 M *91.4 mL = 1*0.986M *V(HCl)

V(HCl) = 18.2 mL

= 0.0182 L

Answer: 0.0182 L

2)

Balanced chemical equation is:

H2SO4 + 2 KOH ---> K2SO4 + 2 H2O

Here:

M(H2SO4)=0.279 M

M(KOH)=0.288 M

V(H2SO4)=35.7 mL

According to balanced reaction:

2*number of mol of H2SO4 =1*number of mol of KOH

2*M(H2SO4)*V(H2SO4) =1*M(KOH)*V(KOH)

2*0.279 M *35.7 mL = 1*0.288M *V(KOH)

V(KOH) = 69.2 mL

= 0.0692 L

Answer: 0.0692 L

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