Question

In: Chemistry

96.0 mL of a NaOH solution of unknown concentration is titrated with 4.00 M hydrochloric acid,...

96.0 mL of a NaOH solution of unknown concentration is titrated with 4.00 M hydrochloric acid, HCl. The end point is reached when 150.0 mL of acid are added to the base. What is the concentration of the original NaOH solution?

a. 1.56 mol/L

b. 3.13 mol/L

c. 6.26 mol/L

d. 12.5 mol/L

Solutions

Expert Solution



Related Solutions

50.0 ml of an acetic acid (CH3COOH) of unknown concentration is titrated with 0.100 M NaOH....
50.0 ml of an acetic acid (CH3COOH) of unknown concentration is titrated with 0.100 M NaOH. After 10.0 mL of the base solution has been added, the pH in the titration flask is 5.30. What was the concentration of the original acetic acid solution? (Ka(CH3COOH) = 1.8 x 10-5)
0.901g KHP is fully titrated with 44.1 mL of an NaOH solution of unknown concentration. What...
0.901g KHP is fully titrated with 44.1 mL of an NaOH solution of unknown concentration. What is the concentration of the NaOH solution? (Report to 3 sig figs).
A 15.00 mL sample of an acetic acid solution of unknown concentration is titrated with 18.82...
A 15.00 mL sample of an acetic acid solution of unknown concentration is titrated with 18.82 mL of a solution of 0.172 M NaOH. Calculate the molarity of the acetic acid solution. Enter your answer in the space provided below to the thousandths place. Do not include units 0.428 g of potassium hydrogen phthalate (KHP, MM = 204.3 g/mol) is measured for reaction with NaOH. The KHP is dissolved in a small amount of water and titrated with 17.31 mL...
A 35.00 mL sample of an unknown H3PO4solution is titrated with a 0.130 M NaOH solution....
A 35.00 mL sample of an unknown H3PO4solution is titrated with a 0.130 M NaOH solution. The equivalence point is reached when 25.83 mLof NaOH solution is added. What is the concentration of the unknown H3PO4 solution? The neutralization reaction is H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4(aq)
a 25.0 mL solution if 0.10 M acetic acid is titrated with 0.1 M NaOH solution....
a 25.0 mL solution if 0.10 M acetic acid is titrated with 0.1 M NaOH solution. the pH equivalence is
a 22.5 ml sample of an acetic acid solution is titrated with a 0.175 M NaOH...
a 22.5 ml sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5 ml of the base is added. What was the concentration of acetic acid in the original 22.5 ml? what is the ph of the equivalence point? (ka (acetic acid) = 1.75 x 10^-5)
1) 20.00 mL of a 0.3000 M lactic acid solution is titrated with 0.1500 M NaOH....
1) 20.00 mL of a 0.3000 M lactic acid solution is titrated with 0.1500 M NaOH. a. What is the pH of the initial solution (before any base is added)? b. What is the pH of the solution after 20.00 mL of the base solution has been added? c. What is the pH of the solution after 40.00 mL of the base solution has been added?
A 50.0 -mL sample of 0.50-M acetic acid, CH3COOH, is titrated with a 0.150M NaOH solution....
A 50.0 -mL sample of 0.50-M acetic acid, CH3COOH, is titrated with a 0.150M NaOH solution. Calculate the pH at equivalence point. (Ka=1.8x10^-5)
50.0 mL of a 0.100 -M HoAc solution is titrated with a 0.100 -M NaOH solution....
50.0 mL of a 0.100 -M HoAc solution is titrated with a 0.100 -M NaOH solution. Calculate the pH at each of the following points. Volume of NaOH added: 0, 5, 10, 25, 40 ,45 , 50 , 55 , 60 , 70 , 80 , 90 , 100
A 15.3 mL sample of vinegar, containing acetic acid, was titrated using 0.809 M NaOH solution....
A 15.3 mL sample of vinegar, containing acetic acid, was titrated using 0.809 M NaOH solution. The titration required 24.06 mL of the base. Assuming the density of the vinegar is 1.01 g/mL, what was the percent (by mass) of acetic acid in the vinegar?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT