A 22.26-mL sample of hydrochloric acid solution requires 35.00 mL of 0.115 M sodium hydroxide for...

A 22.26-mL sample of hydrochloric acid solution requires 35.00 mL of 0.115 M sodium hydroxide for complete neutralization. What is the concentration of the original hydrochloric acid solution?

Expert Solution

HCl(aq) + NaOH(aq) -------------> NaCl(aq) + H2O(l)

1 mole 1 mole

HCl NaOH

M1 = M2 = 0.115M

V1 =22.26ml V2 = 35ml

n1 = 1 n2 = 1

M1V1/n1 = M2V2/n2

M1 = M2V2n1/V1n2

= 0.115*35*1/22.26*1 = 0.18 M

The concentration of hydrochloric acid = 0.18M

queen_honey_blossom answered 1 year ago

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