In: Chemistry
A 22.26-mL sample of hydrochloric acid solution requires 35.00 mL of 0.115 M sodium hydroxide for complete neutralization. What is the concentration of the original hydrochloric acid solution?
HCl(aq) + NaOH(aq) -------------> NaCl(aq) + H2O(l)
1 mole 1 mole
HCl NaOH
M1 = M2 = 0.115M
V1 =22.26ml V2 = 35ml
n1 = 1 n2 = 1
M1V1/n1 = M2V2/n2
M1 = M2V2n1/V1n2
= 0.115*35*1/22.26*1 = 0.18 M
The concentration of hydrochloric acid = 0.18M