In: Statistics and Probability
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 8.3 minutes and a standard deviation of 2.7 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.)
(a) less than 10 minutes
(b) longer than 5 minutes
(c) between 8 and 15 minutes
µ = 8.3
sd = 2.7
a)
= P(Z < 0.63)
= 0.7357
b)
= P(Z > -1.22)
= 1 - P(Z < -1.22)
= 1 - 0.1112
= 0.8888
c)
= P(-0.11 < Z < 2.48)
= P(Z < 2.48) - P(Z < -0.11)
= 0.9934 - 0.4562
= 0.5372