In: Statistics and Probability
The times per week a student uses a lab computer are normally distributed, with a mean of 6.5 hours and a standard deviation of 1.5 hours. A student is randomly selected. Find the following probabilities.
(a) Find the probability that the student uses a lab computer less than 3 hours per week.
(b) Find the probability that the student uses a lab computer between 6 and 8 hours per week.
(c) Find the probability that the student uses a lab computer more than 9 hours per week.
Solution :
Given that ,
mean = = 6.5
standard deviation = =1.5
P(X< 3) = P[(X- ) / < (3-6.5) /1.5 ]
= P(z <-2.33 )
Using z table
=0.0099
probability=0.0099
(B)
P(6< x <8 ) = P[(6-6.5) /1.5 < (x - ) / < (8-6.5) /1.5 )]
= P( -0.33< Z <1 )
= P(Z < 1) - P(Z <-0.33 )
Using z table
= 0.8413-0.3707
probability= 0.4706
(C)
P(x >9 ) = 1 - P(x<9 )
= 1 - P[(x -) / < (9-6.5) /1.5 ]
= 1 - P(z <1.67 )
Using z table
= 1 - 0.9525
= 0.0475
probability=0.0475