Question

In: Statistics and Probability

Total Value Heated Area AC FP $147,021 1,138 YES NO $174,624 1,224 YES YES $213,309 1,456...

Total Value Heated Area AC FP
$147,021 1,138 YES NO
$174,624 1,224 YES YES
$213,309 1,456 YES NO
$252,448 1,461 YES YES
$444,599 2,729 YES YES
$172,996 1,178 YES YES
$181,527 1,251 YES YES
$118,262 1,142 YES YES
$300,095 1,799 YES YES
$292,600 2,478 YES YES
$212,030 1,776 YES YES
$444,032 2,933 YES YES
$238,315 2,531 YES YES
$195,082 1,516 YES YES
$367,572 2,817 YES YES
$737,358 3,910 YES YES
$276,024 1,687 YES YES
$343,997 2,460 YES YES
$204,165 1,437 YES YES
$91,032 904 YES YES
$137,514 1,689 NO NO
$360,554 2,295 YES YES
$319,038 2,200 YES YES
$678,314 1,730 YES YES
$44,811 1,345 NO NO
$182,836 1,116 YES NO
$241,832 1,952 YES YES
$165,907 1,120 YES NO
$155,325 1,450 YES NO
$152,683 1,156 YES YES
  1. Calculate 95% and 99% confidence intervals for the Total Value assessed, Heated area, Air Conditioning, and Fireplaces based on your sample data. Show your work by hand in doing these, showing which formula you are using, giving the zα/2 , standard error and margin of error etc...
  2. Explain what each of the confidence intervals tell you concerning the homes in Wake County. Write these explanations out using full sentences!  Example: We are 95% confident that the population mean assessed value of the homes is... etc.

Solutions

Expert Solution

Total Value assessed:

Level of Significance ,    α =    0.05          
degree of freedom=   DF=n-1=   29          
't value='   tα/2=   2.0452   [Excel formula =t.inv(α/2,df) ]      
                  
Standard Error , SE = s/√n =   155315.5338   / √   30   =   28356.607126
margin of error , E=t*SE =   2.0452   *   28356.60713   =   57995.773445
                  
confidence interval is                   
Interval Lower Limit = x̅ - E =    261530.07   -   57995.773445   =   203534.293222
Interval Upper Limit = x̅ + E =    261530.07   -   57995.773445   =   319525.840112
95%   confidence interval is (   203534.29   < µ <   319525.84   )

----

Level of Significance ,    α =    0.01          
degree of freedom=   DF=n-1=   29          
't value='   tα/2=   2.7564   [Excel formula =t.inv(α/2,df) ]      
                  
Standard Error , SE = s/√n =   155315.5338   / √   30   =   28356.607126
margin of error , E=t*SE =   2.7564   *   28356.60713   =   78161.752159
                  
confidence interval is                   
Interval Lower Limit = x̅ - E =    261530.07   -   78161.752159   =   183368.314508
Interval Upper Limit = x̅ + E =    261530.07   -   78161.752159   =   339691.818825
99%   confidence interval is (   183368.31   < µ <   339691.82   )

Heated area:

Level of Significance ,    α =    0.05          
degree of freedom=   DF=n-1=   29          
't value='   tα/2=   2.0452   [Excel formula =t.inv(α/2,df) ]      
                  
Standard Error , SE = s/√n =   703.0786   / √   30   =   128.363994
margin of error , E=t*SE =   2.0452   *   128.36399   =   262.533845
                  
confidence interval is                   
Interval Lower Limit = x̅ - E =    1796.00   -   262.533845   =   1533.466155
Interval Upper Limit = x̅ + E =    1796.00   -   262.533845   =   2058.533845
95%   confidence interval is (   1533.47   < µ <   2058.53   )

------

Level of Significance ,    α =    0.01          
degree of freedom=   DF=n-1=   29          
't value='   tα/2=   2.7564   [Excel formula =t.inv(α/2,df) ]      
                  
Standard Error , SE = s/√n =   703.0786   / √   30   =   128.363994
margin of error , E=t*SE =   2.7564   *   128.36399   =   353.820703
                  
confidence interval is                   
Interval Lower Limit = x̅ - E =    1796.00   -   353.820703   =   1442.179297
Interval Upper Limit = x̅ + E =    1796.00   -   353.820703   =   2149.820703
99%   confidence interval is (   1442.18   < µ <   2149.82   )

Thanks in advance!

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