In: Statistics and Probability
| 
 5-year Survival  | 
|||
| 
 Treatment  | 
 No  | 
 Yes  | 
 Total  | 
| 
 Yes  | 
 4300  | 
 750  | 
 5050  | 
| 
 No  | 
 7200  | 
 650  | 
 7850  | 
| 
 Total  | 
 11500  | 
 1400  | 
 12900  | 
| 
 Q: is the treatment effective? (Calculate and show the chi-squared test p value in your answer.)  | 
using excel>addin>phstat>nultiple sample test
we have
| Chi-Square Test | ||||||
| Observed Frequencies | ||||||
| 5 year survival | Calculations | |||||
| treatment | no | yes | Total | fo-fe | ||
| yes | 4300 | 750 | 5050 | -201.938 | 201.938 | |
| no | 7200 | 650 | 7850 | 201.938 | -201.938 | |
| Total | 11500 | 1400 | 12900 | |||
| Expected Frequencies | ||||||
| 5 year survival | ||||||
| treatment | no | yes | Total | (fo-fe)^2/fe | ||
| yes | 4501.938 | 548.062 | 5050 | 9.058088 | 74.40572 | |
| no | 6998.062 | 851.938 | 7850 | 5.827178 | 47.8661 | |
| Total | 11500 | 1400 | 12900 | |||
| Data | ||||||
| Level of Significance | 0.05 | |||||
| Number of Rows | 2 | |||||
| Number of Columns | 2 | |||||
| Degrees of Freedom | 1 | |||||
| Results | ||||||
| Critical Value | 3.841459 | |||||
| Chi-Square Test Statistic | 137.1571 | |||||
| p-Value | 1.11E-31 | |||||
| Reject the null hypothesis | ||||||
H0:the treatment is not effecticve
Ha:the treatment is effecticve
the value of chi square is 137.157
p value is 0.000
since p value is less than 0.05 so we reject ho and conclude that the treatment is effecticve