Question

BIO 260 SP20 Assignment #6 One Sample t-tests. INSTRUCTIONS Provide responses on the Assignment 6 Answer Sheet

1. A new drug that is meant to increase hematocrit in humans and that may be a cheaper alternative to EPOGEN is being tested. A clinical trial was performed in which fifteen volunteers took the drug and had their hematocrit measured. The known mean hematocrit in humans is 45%.

Data:

37.8 46.8 42.8 38.3 42.7 47.3 49 39.9 43.6 45.7 52.9 43.6 47.4 47.3 43.4

2. Consider a population of lizards living on an island. We believe that they may be members of a species called Tribolonotus gracilis. The mean length of Tribolonotus gracilis is known to be 8cm. The following length values (cm) were obtained for a sample of individuals from the island:

11.3 11.5 9.2 11 6.9 8.9 6.9 11.3

1.  Hematocrit

A.  The  “population” we are estimating the parameters for with our sample is...

B. H₀                                                                H_A

C. Sample

            n

            Mean

            Variance

            SD

            SE

D. TCALC=

E. TCrit =

G. Statistical Conclusion...

H. Biological Conclusion...

2. Lizards

A. H₀                                                                H_A

B. Tcalc =                   Tcrit  =.                =

Statistical Conclusionr

Biological Conclusion

Answer 1

1:

A: Population: All humans

B:

Hypotheses are:

C:

Following table shows the calculations:

	X	(X-mean)^2
	37.8	45.792289
	46.8	4.986289
	42.8	3.122289
	38.3	39.275289
	42.7	3.485689
	47.3	7.469289
	49	19.651489
	39.9	21.780889
	43.6	0.935089
	45.7	1.283689
	52.9	69.438889
	43.6	0.935089
	47.4	8.025889
	47.3	7.469289
	43.4	1.361889
Total	668.5	235.013335

The standard error of estimate is

D:

E:

Hence,

TCrit =1.761

G:

H:

There is no evidence that new drug increases hematocrit in humans

------------------------------------------------

2;

A:

B:

B:

Folloiwng table shows the calculations for mean and SD:

	X	(X-mean)^2
	11.3	2.805625
	11.5	3.515625
	9.2	0.180625
	11	1.890625
	6.9	7.425625
	8.9	0.525625
	6.9	7.425625
	11.3	2.805625
Total	77	26.575

Hence,

Tcalc = 2.359,

Tcrit  = 2.365

Statistical conclusion:

Biological conclusion: It seem that they may be members of a species called Tribolonotus gracilis.