What volume (in liters) of 0.1000 M NaOH is required to neutralize 25.00 mL of 0.0700...

What volume (in liters) of 0.1000 M NaOH is required to neutralize 25.00 mL of 0.0700 M H₃PO₄

I am not sure how to set this problem up, I kind of have an idea but I lost also

Expert Solution

3NaOH(aq) + H3PO4(aq) --------------> Na3PO4(aq) + 3H2O(l)

3 moles 1 mole

NaOH H3PO4

M1 = 0.1M M2 = 0.07M

V1 = V2 = 25ml

n1 = 3 n2 = 1

M1V1/n1 = M2V2/n2

V1 = M2V2n1/M1n2

= 0.07*25*3/0.1*1 = 52.5ml = 0.0525L

volume of NaOH = 0.0525L >>>>>>>answer

queen_honey_blossom answered 2 years ago

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