In: Chemistry
If 47.58 mL of a standard 0.3155 M
NaOH solution is required to neutralize 12.61 mL of
H2SO4, what
is the molarity of the acid solution?
________ M
H2SO4 + 2NaOH ----------> Na2So4 + 2H2O
1 mole 2 moles
H2So4 NaOH
M1 = M2 = 0.3155M
V1 = 12.61ml V2 = 47.58ml
n1 = 1 n2 = 2
M1V1/n1 = M2V2/n2
M1 = M2V2n1/V1n2
= 0.3155*47.58*1/12.61*2 = 0.595M
molarity of H2So4 = 0.595M