If 47.58 mL of a standard 0.3155 M NaOH solution is required to neutralize 12.61 mL...

If 47.58 mL of a standard 0.3155 M NaOH solution is required to neutralize 12.61 mL of H₂SO₄, what is the molarity of the acid solution?

________ M

Expert Solution

H2SO4 + 2NaOH ----------> Na2So4 + 2H2O

1 mole 2 moles

H2So4 NaOH

M1 = M2 = 0.3155M

V1 = 12.61ml V2 = 47.58ml

n1 = 1 n2 = 2

M1V1/n1 = M2V2/n2

M1 = M2V2n1/V1n2

= 0.3155*47.58*1/12.61*2 = 0.595M

molarity of H2So4 = 0.595M

queen_honey_blossom answered 1 year ago

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