Question

In: Statistics and Probability

Eight measurements were made on the inside diameter of forged piston rings used in an automobile...

Eight measurements were made on the inside diameter of forged piston rings used in an automobile engine. The data (in millimeters) are 74.001, 74.003, 74.015, 74.000, 74.005, 74.002, 74.006, and 74.000. Calculate the sample mean and sample standard deviation. Round your answers to 3 decimal places. Sample mean = Sample standard deviation =

Solutions

Expert Solution

Solution:

x x2
74.001 5476.148
74.003 5476.444
74.015 5478.2202
74 5476
74.005 5476.74
74.002 5476.296
74.006 5476.888
74 5476
--- ---
x=592.032 x2=43812.7363

The sample mean is

Mean     = (x / n) )



=74.001+74.003+74.015+74+74.005+74.002+74.006+748

=592.032 /8

=74.004

Sample mean =74.004

The sample standard is S

  S =( x2 ) - (( x)2 / n ) n -1

=(43812.7363-(592.032)28 )/ 7

=( 43812.7363-43812.7361) /7

=0.0002 /7

=0

= 0.005

Sample standard deviation = 0.005


Related Solutions

A manufacturer produces piston rings for an automobile engine. It is known that the ring diameter...
A manufacturer produces piston rings for an automobile engine. It is known that the ring diameter is normally distributed with σ = 0.001 millimeters. When a random sample of 16 rings is collected, the sample mean of the rings’ diameters is of x- = 74.036 millimeters. a.) In order to find a confidence interval for the true mean piston ring diameter, which distribution table would you use? b.) Find the lower bound of a 95% confidence interval for the mean...
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is...
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is Normally Distributed with ? = 0.001 ??. A random sample of 9 rings has a mean diameter of ? = 74.036 ?? a. What is a 95% ?????????? ???????? for the true mean diameter of the piston rings. Use the given ? = 0.001 ??. b. Interpret the ?????????? ???????? constructed in part (a) c. For mathematical purposes, assume for a moment that the...
Information for Problems 1 – 9: The diameter of piston rings produced for automobile engines is...
Information for Problems 1 – 9: The diameter of piston rings produced for automobile engines is known to be normally distributed with a population standard deviation,std, equal to 0.100 millimeters. The last ten piston rings produced by a particular manufacturer have the following diameters (in millimeters): 74.036, 74.432, 74.212, 74.071, 73.968, 74.231, 73.899, 74.035, 74.079 and 73.995 1.     If you were to calculate a confidence interval for the mean diameter of piston rings, would you use a Z-Interval or a...
Piston rings are mass-produced. The target internal diameter is 45mm but records show that the diameters...
Piston rings are mass-produced. The target internal diameter is 45mm but records show that the diameters are normally distributed with mean 45mm and standard deviation 0.05 mm. An acceptable diameter is one within the range 44.95 mm to 45.05 mm. (i) What proportion of the output is unacceptable? (ii) Above what diameter do the 40% largest diameters lie?
The inside diameter of a piston ring is normally distributed with a mean of 10 cm...
The inside diameter of a piston ring is normally distributed with a mean of 10 cm and a standard deviation of 0.04 cm. What is the probability that a piston ring will have an inside diameter less than 10.075 cm? What is the probability that a piston ring will have an inside diameter between 9.94 and 10.045 cm? What proportion of rings will have inside diameters exceeding 10.066 cm? Suppose that five piston rings are randomly selected. What is the...
The inside diameter of a randomly selected piston ring is a random variable with mean value...
The inside diameter of a randomly selected piston ring is a random variable with mean value 11 cm and standard deviation 0.06 cm. (a) If X is the sample mean diameter for a random sample of n = 16 rings, where is the sampling distribution of X centered and what is the standard deviation of the X distribution? (Enter your standard deviation to five decimal places.) center     cm standard deviation     cm (b) Answer the questions posed in part (a) for...
The inside diameter of a randomly selected piston ring is a random variable with mean value...
The inside diameter of a randomly selected piston ring is a random variable with mean value 15 cm and standard deviation 0.07 cm. Suppose the distribution of the diameter is normal. (Round your answers to four decimal places.) (a) Calculate P(14.99 ≤ X ≤ 15.01) when n = 16. P(14.99 ≤ X ≤ 15.01) = (b) How likely is it that the sample mean diameter exceeds 15.01 when n = 25? P(X ≥ 15.01) =
500 g of saturated liquid water is contained in a piston-cylinder arrangement. The inside diameter of...
500 g of saturated liquid water is contained in a piston-cylinder arrangement. The inside diameter of the cylinder is 100 mm. The water is heated at a constant pressure of 150 kPa until it becomes saturated vapor. Determine (a) the distance through which the piston is raised, and (b) the amount of energy transferred to the water
A bearing used in an automotive application is required to have a nominal inside diameter of...
A bearing used in an automotive application is required to have a nominal inside diameter of 1.5 inches. A random sample of 25 bearings is selected and the average inside diameter of these bearings is 1.4975 inches. Bearing diameter is known to be normally distributed with standard deviation 1inch. (a) Test the hypotheses 1.5 versus 1.5 using 0.01 The true mean hole diameter Entry field with correct answer significantly different from 1.5 in. at alpha equals 0.01. (b) What is...
A neon sign is made of glass tubing whose inside diameter is 2.5 cm and whose...
A neon sign is made of glass tubing whose inside diameter is 2.5 cm and whose length is 5.5 m. If the sign contains neon at a pressure of 1.73 torr at 37 ∘C, how many grams of neon are in the sign? (The volume of a cylinder is πr2h.) Express your answer using two significant figures.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT