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In: Math
Question 1: Eight measurements were made on the inside diameter of forged piston rings used in...
Question 1:
Eight measurements were made on the inside diameter of forged piston rings used in an automobile engine. The data (in millimeters) are 74.001, 74.003, 74.015, 74.000, 74.005, 74.002, 74.005, and 74.004.
- Compute the sample mean and sample standard deviation of the temperature data.
- Graph a histogram of the data.
- Graph a normal probability plot of the data.
- Comment on the data.
Question 2:
The April 22, 1991 issue of Aviation Week and Space Technology reports that during Operation Desert Storm, U.S. Airforce F-117A pilots flew 1270 combat sorties for a total of 6905 hours. What is the mean duration of an F-117A mission during this operation? Why is the parameter you have calculated a population mean?
Solutions
milcah answered 2 months agoRelated Solutions
Eight measurements were made on the inside diameter of forged piston rings used in an automobile...
Eight measurements were made on the inside diameter of forged
piston rings used in an automobile engine. The data (in
millimeters) are 74.001, 74.003, 74.015, 74.000, 74.005, 74.002,
74.006, and 74.000. Calculate the sample mean and sample standard
deviation. Round your answers to 3 decimal places. Sample mean =
Sample standard deviation =
Information for Problems 1 – 9: The diameter of piston rings produced for automobile engines is...
Information for Problems 1 – 9: The diameter of
piston rings produced for automobile engines is known to be
normally distributed with a population standard deviation,std,
equal to 0.100 millimeters. The last ten piston rings produced by a
particular manufacturer have the following diameters (in
millimeters): 74.036, 74.432, 74.212, 74.071, 73.968, 74.231,
73.899, 74.035, 74.079 and 73.995
1. If you were
to calculate a confidence interval for the mean diameter of piston
rings, would you use a Z-Interval or a...
A manufacturer produces piston rings for an automobile engine. It is known that the ring diameter...
A manufacturer produces piston rings for an automobile engine.
It is known that the ring diameter is normally distributed with σ =
0.001 millimeters. When a random sample of 16 rings is collected,
the sample mean of the rings’ diameters is of x- = 74.036
millimeters.
a.) In order to find a confidence interval for the true mean
piston ring diameter, which distribution table would you use?
b.) Find the lower bound of a 95% confidence interval for the
mean...
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is...
A manufacturer produces piston rings for an automobile engine.
It is known that ring diameter is Normally Distributed with ? =
0.001 ??. A random sample of 9 rings has a mean diameter of ? =
74.036 ??
a. What is a 95% ?????????? ???????? for the true mean diameter
of the piston rings. Use the given ? = 0.001 ??.
b. Interpret the ?????????? ???????? constructed in part (a)
c. For mathematical purposes, assume for a moment that the...
Piston rings are mass-produced. The target internal diameter is 45mm but records show that the diameters...
Piston rings are mass-produced. The target internal diameter is
45mm but records show
that the diameters are normally distributed with mean 45mm and
standard deviation 0.05
mm. An acceptable diameter is one within the range 44.95 mm to
45.05 mm.
(i) What proportion of the output is unacceptable?
(ii) Above what diameter do the 40% largest diameters lie?
The inside diameter of a piston ring is normally distributed with a mean of 10 cm...
The inside diameter of a piston ring
is normally distributed with a mean of 10 cm and a standard
deviation of 0.04 cm.
What is the probability that a piston ring will have an inside
diameter less than 10.075 cm?
What is the probability that a piston ring will have an inside
diameter between 9.94 and 10.045 cm?
What proportion of rings will have inside diameters exceeding
10.066 cm?
Suppose that five piston rings are randomly selected. What is
the...
The inside diameter of a randomly selected piston ring is a random variable with mean value...
The inside diameter of a randomly selected piston ring is a
random variable with mean value 11 cm and standard deviation 0.06
cm.
(a) If
X
is the sample mean diameter for a random sample of n =
16 rings, where is the sampling distribution of
X
centered and what is the standard deviation of the
X
distribution? (Enter your standard deviation to five decimal
places.)
center
cm
standard deviation
cm
(b) Answer the questions posed in part (a) for...
The inside diameter of a randomly selected piston ring is a random variable with mean value...
The inside diameter of a randomly selected piston ring is a
random variable with mean value 15 cm and standard deviation 0.07
cm. Suppose the distribution of the diameter is normal. (Round your
answers to four decimal places.)
(a) Calculate
P(14.99 ≤ X ≤ 15.01)
when n = 16.
P(14.99 ≤ X ≤ 15.01)
=
(b) How likely is it that the sample mean diameter exceeds 15.01
when n = 25?
P(X ≥ 15.01)
=
A manufacturing process produces piston rings, with ID (inner diameter) dimension as shown above. Process variation...
A manufacturing process produces piston rings, with ID (inner
diameter) dimension as shown above. Process variation causes the ID
to be normally distributed, with a mean of 10.021 cm and a standard
deviation of 0.040 cm. a. What percentage of piston rings will have
ID exceeding 10.075 cm? What percentage of piston rings will have
ID exceeding 10.080 cm? (4) b. What is the probability that a
piston ring will have ID between 9.970 cm and 10.030 cm? (This is...
500 g of saturated liquid water is contained in a piston-cylinder arrangement. The inside diameter of...
500 g of saturated liquid water is contained in a
piston-cylinder arrangement. The inside diameter of the cylinder is
100 mm. The water is heated at a constant pressure of 150 kPa until
it becomes saturated vapor. Determine (a) the distance through
which the piston is raised, and (b) the amount of energy
transferred to the water
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