A manufacturing process produces piston rings, with ID (inner diameter) dimension as shown above. Process variation...

A manufacturing process produces piston rings, with ID (inner diameter) dimension as shown above. Process variation causes the ID to be normally distributed, with a mean of 10.021 cm and a standard deviation of 0.040 cm. a. What percentage of piston rings will have ID exceeding 10.075 cm? What percentage of piston rings will have ID exceeding 10.080 cm? (4) b. What is the probability that a piston ring will have ID between 9.970 cm and 10.030 cm? (This is the customer’s specification that the supplier tries to provide .) (ie.) If the specification is “9.970cm < ID < 10.030cm”, what %’age of piston rings are “out of spec”? c. Half (50%) of all piston rings have ID below 10.021 cm. What is the dimension corresponding to the smallest 10%, and what is the dimension corresponding to the largest 10%? What is the dimension corresponding to the smallest 20%, and what is the dimension corresponding to the largest 20%

Solutions

Expert Solution

samet mamat answered 2 hours ago

Next > < Previous

Related Solutions

A manufacturer produces piston rings for an automobile engine. It is known that the ring diameter...

A manufacturer produces piston rings for an automobile engine. It is known that the ring diameter is normally distributed with σ = 0.001 millimeters. When a random sample of 16 rings is collected, the sample mean of the rings’ diameters is of x- = 74.036 millimeters. a.) In order to find a confidence interval for the true mean piston ring diameter, which distribution table would you use? b.) Find the lower bound of a 95% confidence interval for the mean...

A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is...

A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is Normally Distributed with ? = 0.001 ??. A random sample of 9 rings has a mean diameter of ? = 74.036 ?? a. What is a 95% ?????????? ???????? for the true mean diameter of the piston rings. Use the given ? = 0.001 ??. b. Interpret the ?????????? ???????? constructed in part (a) c. For mathematical purposes, assume for a moment that the...

Information for Problems 1 – 9: The diameter of piston rings produced for automobile engines is...

Information for Problems 1 – 9: The diameter of piston rings produced for automobile engines is known to be normally distributed with a population standard deviation,std, equal to 0.100 millimeters. The last ten piston rings produced by a particular manufacturer have the following diameters (in millimeters): 74.036, 74.432, 74.212, 74.071, 73.968, 74.231, 73.899, 74.035, 74.079 and 73.995 1. If you were to calculate a confidence interval for the mean diameter of piston rings, would you use a Z-Interval or a...

Piston rings are mass-produced. The target internal diameter is 45mm but records show that the diameters...

Piston rings are mass-produced. The target internal diameter is 45mm but records show that the diameters are normally distributed with mean 45mm and standard deviation 0.05 mm. An acceptable diameter is one within the range 44.95 mm to 45.05 mm. (i) What proportion of the output is unacceptable? (ii) Above what diameter do the 40% largest diameters lie?

Eight measurements were made on the inside diameter of forged piston rings used in an automobile...

Eight measurements were made on the inside diameter of forged piston rings used in an automobile engine. The data (in millimeters) are 74.001, 74.003, 74.015, 74.000, 74.005, 74.002, 74.006, and 74.000. Calculate the sample mean and sample standard deviation. Round your answers to 3 decimal places. Sample mean = Sample standard deviation =

HK Masks Limited produces and sells masks. Fixed manufacturing overhead incurred for the above production process...

HK Masks Limited produces and sells masks. Fixed manufacturing overhead incurred for the above production process totaled $800,000. Net operating income under variable costing was three million dollars. The company did not have beginning inventory, units produced were 250,000 and units sold were 150,500. Required: a. Calculate the units of ending inventory . b. Compute the manufacturing overhead per unit absorbed in the ending inventory. c. Use vertical 3 rows schedule to show the variances between the variable costing and...

The process that produces a machined part has a normal distribution with the average diameter of...

The process that produces a machined part has a normal distribution with the average diameter of 7.2 cm and a standard deviation of 0.35 cm. What is the probability that a part will have a diameter between 7.1 cm and 7.6 cm? Select one: a. 0.4859 b. 0.8734 c. 0.3875 d. 0.2609

4. A manufacturing plant produces memory chips to be used in cardiac pacemakers.The manufacturing process produces...

4. A manufacturing plant produces memory chips to be used in cardiac pacemakers.The manufacturing process produces a mix of “good” chips and “bad” chips. The lifetime of good chips follows an exponential law with a rate of failure ??, that is: P[chip still functioning after time ?] = ?−?t The lifetime of bad chips also follows an exponential law, but with a much faster failure rate of 500*?. a. Suppose the fraction of bad chips in a typical batch is?.What...

You are working on a manufacturing process that should produce products that have a diameter of...

You are working on a manufacturing process that should produce products that have a diameter of 3/4 of an inch. You take a random sample of 35 products and find the diameter to be 13/16 of an inch with a standard deviation of 5/32 of an inch. 3. Calculate a 95% confidence interval around the sample mean. What do you notice about this interval relative to the desired diameter and how does this relate to your answers in questions 1...

Mercedes tires at Tracy's plant are produced in a manufacturing process and the diameter is VERY...

Mercedes tires at Tracy's plant are produced in a manufacturing process and the diameter is VERY important factor that must be controlled. From sample sizes of 10 tires produced each day, the mean sample of this diameter have been as follows: SAMPLES Day #1 #2 #3 #4 #5 #6 #7 #8 #9 #10 Mean 1 22 22 15 18 15 22 22 12 17 21 18.6 2 22 13 15 13 20 11 18 19 10 20 16.1 3 15...

Subjects