In the reaction of 5.44 g of H2 with excess N2, a chemist isolates 7.56 g...

In the reaction of 5.44 g of H₂ with excess N₂, a chemist isolates 7.56 g of NH₃. what is the percent yield in the reaction?

Expert Solution

3 H2 + N2 -----------------> 2 NH3

6.00 g 34 g

5.44 g ??

6 g H2 --------------> 34 g NH3

5.44 g H2 ---------------> ??

theoretical yield of NH3 = 5.44 x 34 / 6 = 30.83 g

actual yield = 7.56 g

percent yield = actual / theoretical ) x 100

= 7.56 / 30.8) x 100

percent yield = 24.5 %

queen_honey_blossom answered 2 years ago

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