Consider the reaction: 3 H2 (g) + N2 (g) ⇋ 2 NH3 (g) In a given...

Consider the reaction:

3 H₂ (g) + N₂ (g) ⇋ 2 NH₃ (g)

In a given reaction, the initial concentrations of reactants and product are: [H₂] = 0.150 M; [N₂] = 0.300 M ; [NH₃] = 0.000 M

If the equilibrium concentration of H₂ is 0.0900 M, what is K_c for the reaction under these conditions?

Solutions

Expert Solution

3 H₂ (g) + N₂ (g) ⇋ 2 NH₃ (g)

I 0.15 0.3 0

C - 3*0.02 -0.02 2*0.02

E 0.09 0.28 0.04

Kc = [NH3]²/[H2]³ {N2]

= (0.04)^2/(0.09)^3 *(0.28) = 7.84>>>>>>answer

queen_honey_blossom answered 1 year ago

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