In: Statistics and Probability
1. If the random variable x has a Poisson Distribution with mean
μ = 53.4, find the maximum usual value
for x.
Round your answer to two decimal places.
2.
In one town, the number of burglaries in a week has a Poisson distribution with mean μ = 7.2. Let variable x denote the number of burglaries in this town in a randomly selected month. Find the smallest usual value for x. Round your answer to three decimal places.
(HINT: Assume a month to be exactly 4 weeks)
Solution:
Question 1) Given: the random variable x has a Poisson Distribution with mean μ = 53.4.
For Poisson distribution: Mean = Variance = μ = 53.4.
Standard Deviation of Poisson distribution is:
We have to find the maximum usual value for x.
Maximum usual value for x =
Maximum usual value for x =
Maximum usual value for x =
Maximum usual value for x =
Question 2)
Given: the number of burglaries in a week has a Poisson distribution with mean μ = 7.2.
x = the number of burglaries in this town in a randomly selected month.
Since mean is given for a week and x is defined per month, so we need to find mean number of burglaries in a month.
For a month number of weeks = 4
Thus new mean = 4 * μ = 4 * 7.2 = 28.80
and
Thus
The smallest usual value for x =
The smallest usual value for x =
The smallest usual value for x =
The smallest usual value for x =
The smallest usual value for x =
The smallest usual value for x =