Question
In: Statistics and Probability
Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an...
Consider the accompanying data on breaking load (kg/25 mm width)
for various fabrics in both an unabraded (U) condition and an
abraded (A) condition.
Use the paired t test to test:
H0: μD = 0 versus
Ha: μD >
0
at significance level 0.01. (Use μD =
μU-A.)
Note: The data below is formatted such that you can copy and
paste it into R.
| Fabric | ||||||||
|---|---|---|---|---|---|---|---|---|
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | |
| U = c( | 36.5, | 55.0, | 51.2, | 38.7, | 43.2, | 48.8, | 25.6, | 49.6) |
| A = c( | 28.5, | 20.0, | 46.0, | 34.0, | 36.5, | 52.5, | 26.5, | 46.5) |
Calculate the mean difference and standard deviation.
| d = | |
| sd = |
Compute the test statistic value. (Round your answer to three
decimal places.)
t =
p-value =
State the conclusion in the problem context.
Reject H0. The data suggests a significant mean difference in breaking load for the two fabric load conditions.Fail to reject H0. The data suggests a significant mean difference in breaking load for the two fabric load conditions. Reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.Fail to reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
Solutions
Expert Solution
Let us denote the difference
d = U - A
The conclusion in the problem context :
Fail to reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
orchestra answered 1 year agoRelated Solutions
Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both an...
Consider the accompanying data on breaking load (kg/25 mm width)
for various fabrics in both an unabraded condition and an abraded
condition. Use the paired t test to test
H0: μD = 0 versus
Ha: μD > 0 at
significance level 0.01. (Use μD =
μU − μA.)
Fabric
1
2
3
4
5
6
7
8
U
36.5
55.0
51.3
38.5
43.2
48.8
25.6
49.8
A
28.5
20.0
46.0
34.5
36.5
52.5
26.5
46.5
Calculate the test statistic and...
A) Consider the accompanying data on breaking load (kg/25 mm width) for various fabrics in both...
A)
Consider the accompanying data on breaking load (kg/25 mm width)
for various fabrics in both an unabraded condition and an abraded
condition. Use the paired t test to test
H0: μD = 0 versus
Ha: μD > 0 at
significance level 0.01. (Use μD =
μU − μA.)
Fabric
1
2
3
4
5
6
7
8
U
36.2
55.0
51.5
38.9
43.2
48.8
25.6
49.5
A
28.5
20.0
46.0
34.5
36.0
52.5
26.5
46.5
Calculate the test statistic...
A textile manufacturer wanted to know if the breaking load (kg/25 mm width) is greater for...
A textile manufacturer wanted to know if the breaking load
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that were abraded. Abraded fabrics are produced by the use of
friction to produce surface wear on the fabric. The manufacturer
randomly selected equal-sized sections of 13 of their fabrics. Each
section was then equally divided into two pieces, with the abrasion
process being applied to one of them. The tensile strength
measurements were taken for all of the fabric...
A textile manufacturer wanted to know if the breaking load (kg/25 mm width) is greater for...
A textile manufacturer wanted to know if the breaking load
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friction to produce surface wear on the fabric. The manufacturer
randomly selected equal-sized sections of 21 of their fabrics. Each
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The data file contains displacement (in mm)-load (in N) data for a mechanical test that was...
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a. (5 pts.) Using the data and a computer program (such as
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1
2
3
1
0.12
0.20
0.27
2
0.08
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0.22
(a) Suppose the sample consisted of n = 100 people. Use
the chi-squared test for independence with significance level 0.10.
State the appropriate hypotheses
.H0:
pij =
pi
pj
for every pair (i, j)
Ha:...
Which requires more work, lifting a 25 -kg load a vertical distance of 8.5 meters or...
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Refer to the accompanying data set and use the 25 home voltage measurements to construct a...
Refer to the accompanying data set and use the 25 home voltage
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classes. Begin with a lower class limit of
127.7127.7
volts, and use a class width of 0.2 volt. Does the result
appear to have a normal distribution? Why or why not?
LOADING...
Click the icon to view the data.
Complete the frequency distribution below.
Voltage (volts)
Frequency
127.7127.7minus−nothing
nothing
nothingminus−nothing
nothing
nothingminus−nothing
nothing
nothingminus−nothing
nothing
nothingminus−nothing
nothing
(Type integers or...
The accompanying table provides the data for 100 room inspections at each of 25 hotels in...
The accompanying table provides the data for 100 room
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Formulate a one-sample hypothesis test for a proportion and
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functions. Use a level of significance of 0.05.
Sample
Rooms Inspected
Nonconforming Rooms
Fraction Nonconforming
1
100
4
0.04
2
100
1
0.01
3
100
0
0
4
100
1...
Question 1: Refer to accompanying data set and use the 25 home voltage measurements to construct...
Question 1: Refer to accompanying data set and use the
25 home voltage measurements to construct a frequency distribution
with five classes. Begin with a lower class limit of 121.7 volts,
and use a class width of 0.2 volt. Does the result appear to have a
normal distribution? Why or why not?
Voltage Measurements from a Home
Day
Home (volts)
Day
Home (volts)
Day
Home (volts)
Day
Home (volts)
1
121.9
8
121.9
14
122.3
20
122.6
2
122.4...
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