Question

In: Statistics and Probability

Consider the accompanying 2 × 3 table displaying the sample proportions that fell in the various...

Consider the accompanying 2 × 3 table displaying the sample proportions that fell in the various combinations of categories (e.g., 12% of those in the sample were in the first category of both factors).

1 2 3
1 0.12 0.20 0.27
2 0.08 0.11 0.22

(a) Suppose the sample consisted of n = 100 people. Use the chi-squared test for independence with significance level 0.10. State the appropriate hypotheses

.H0: pij =

pi
pj

for every pair (i, j)
Ha: at least one pij

pi
pj

H0: pij

pi
pj

for every pair (i, j)
Ha: at least one pij =

pi
pj

    

H0: pij = pi · pj

for every pair (i, j)

Ha: at least one pijpi · pj

H0: pijpi · pj

for every pair (i, j)

Ha: at least one pij = pi · pj


Calculate the test statistic. (Round your answer to two decimal places.)
χ2 =  

What can be said about the P-value for the test?

P-value < 0.0050.005 < P-value < 0.01    0.01 < P-value < 0.0250.025 < P-value < 0.050.05 < P-value < 0.10P-value > 0.10


State the conclusion in the problem context.

Reject H0. An individual's category with respect to factor 1 is not independent of the category with respect to factor 2.Fail to reject

H0. An individual's category with respect to factor 1 is independent of the category with respect to factor 2.   

Reject H0. An individual's category with respect to factor 1 is independent of the category with respect to factor 2.

Fail to reject H0. An individual's category with respect to factor 1 is not independent of the category with respect to factor 2.


(b) Suppose the sample consisted of n = 1000 people. Use the chi-squared test for independence with significance level 0.10.
Calculate the test statistic. (Round your answer to two decimal places.)
χ2 =  

What can be said about the P-value for the test?

P-value < 0.005

0.005 < P-value < 0.01   

0.01 < P-value < 0.025

0.025 < P-value < 0.05

0.05 < P-value < 0.10

P-value > 0.10


State the conclusion in the problem context.

Fail to reject H0. An individual's category with respect to factor 1 is independent of the category with respect to factor 2.Reject

H0. An individual's category with respect to factor 1 is independent of the category with respect to factor 2.   

Reject H0. An individual's category with respect to factor 1 is not independent of the category with respect to factor 2.

Fail to reject H0. An individual's category with respect to factor 1 is not independent of the category with respect to factor 2.


(c) What is the smallest sample size n for which these observed proportions would result in rejection of the independence hypothesis? (Round your answer up to the next whole number.)
n =  

Solutions

Expert Solution

Ho: pij =pi/pj

Ha: pij ≠ pi/pj for at least one pair

Applying chi square test of independence:
Expected Ei=row total*column total/grand total 1st 2nd 3rd Total
1st 11.800 18.290 28.910 59
2nd 8.200 12.710 20.090 41
total 20 31 49 100
chi square    χ2 =(Oi-Ei)2/Ei 1st 2nd 3rd Total
1st 0.0034 0.1599 0.1262 0.2895
2nd 0.0049 0.2301 0.1816 0.4165
total 0.0083 0.3899 0.3078 0.7060
test statistic X2 = 0.71

P-value > 0.10

Fail to reject

H0. An individual's category with respect to factor 1 is independent of the category with respect to factor 2.   

b)

Applying chi square test of independence:
Expected Ei=row total*column total/grand total 1st 2nd 3rd Total
1st 118.000 182.900 289.100 590
2nd 82.000 127.100 200.900 410
total 200 310 490 1000
chi square    χ2 =(Oi-Ei)2/Ei 1st 2nd 3rd Total
1st 0.0339 1.5987 1.2619 2.8945
2nd 0.0488 2.3006 1.8159 4.1653
total 0.0827 3.8994 3.0778 7.0598
test statistic X2 = 7.060

0.025 < P-value < 0.05

Reject H0. An individual's category with respect to factor 1 is not independent of the category with respect to factor 2.
c(

n=653


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