Question
In: Statistics and Probability
What is the margin of error for a 99% CI for a mean, when the sample...
What is the margin of error for a 99% CI for a mean, when the sample size is 8, the sample average is 152, the sample std dev is 30, and the sample was drawn from a Normal population? (Enter your answer to two decimals: ex: 12.34).
A 90% confidence interval for the population mean is 30 < mu < 50. What is the sample mean?
A sample of 8 female college students consumes an average of 10 liters of alcohol per month, with a sample standard deviation of 3.9 liters. Monthly alcohol consumption is Normally distributed. What is the margin of error for a 90% Confidence Interval for the mean? (Leave your answer to two decimal places, ex: 18.12)
Solutions
Expert Solution
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Sample mean = (lower+upper)/2 = (30+50)/2 = 40
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orchestra answered 2 years agoRelated Solutions
Determine the margin of error for a 99% confidence interval to estimate the population mean when...
Determine the margin of error for a 99% confidence interval to
estimate the population mean when s = 43 for the sample sizes
below. a) n=12 b) n=25 c) n=46 a) The margin of error for a
99% confidence interval when n=12 is _.
Determine the margin of error for a 99% confidence interval to estimate the population mean when...
Determine the margin of error for a 99% confidence interval to
estimate the population mean when s=45 for the sample sizes of
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Determine the margin of error for a confidence interval to
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Find the sample size needed to give, with 99% confidence a
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σ =10 n = _____
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Sigma known Ratings Population Standard Deviation 2.64 Mean 42.95384615 95% CI Margin of Error Standard Error...
Sigma known
Ratings
Population Standard Deviation
2.64
Mean
42.95384615
95% CI Margin of Error
Standard Error
0.327747828
0.641805331
Median
43
95% Confidence Interval
Mode
44
42.31204082
43.59565148
Standard Deviation
2.642387469
99% CI Margin of Error
Sample Variance
6.982211538
0.843188126
Kurtosis
-0.392154755
99% Confidence Interval
Skewness
-0.446608112
42.11065803
Range
12
43.79703428
Minimum
36
Maximum
48
Sum
2792
Sigma Unknown
Count
65
95% Confidence Interval
Confidence Level(95.0%)
0.654751556
42.2990946
43.60859771
State the 95% confidence interval for sigma
unknown.
What is the multiplier...
Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for...
Find the mean, standard deviation,
80%, 95%, and 99% confidence intervals, and margin of error for
those intervals. Show all work.
$32,096
$29,716
$29,227
$27,209
$22,794
$19,306
$19,238
$19,164
18,994
$18,329
$17,978
$17,626
$16,823
$16,709
$15,967
$15,921
$15,908
$15,905
$15,638
$15,629
$14,414
$14,229
$14,137
$14,051
$13,907
$13,776
$13,281
$12,739
$12,300
$11,994
$11,262
$11,112
$10,984
$10,824
$10,823
$10,448
$10,081
$9,883
$9,668
$9,663
$9,337
$8,855
$8,741
$8,596
$8,385
$7,204
$7,072
$6,503
$5,653
$4,602
How large a sample would be needed to form a 99% confidence interval for the mean ticket revenue if desired margin of error is 5 cents?
An inexperienced fair promoter has printed 10,000 tickets for the year Eurelia Solstice fair. There are 5,000 blue tickets for adults, costing $10 each, 3000 green tickets for children, costing $5 each, and 2,000 gold tickets for seniors, costing $4 each. A random sample of 200 Eurelians intending to go to the fair have has been selected by EURELIFAX, the major polling company in Eurelia. in the sample there are a 120 adults, 55 children, and 25 series seniors....
1) margin of error: 0.025; confidence level: 99%; p = .25. The minimum sample size is n...
1) margin of error: 0.025; confidence level: 99%; p =
.25. The minimum sample size is n = .
2) margin of error: 0.04; confidence level 98%; p = .7. The minimum
sample size is n = .
3) margin of error: 3%; confidence level 95%; p = .5. The
minimum sample size is n = .
4) margin of error 2%; confidence level 97%; p = .15. The
minimum sample size is n = .
5) margin of error 1.5%; confidence level 96%; p...
Determine the margin of error for a 99% confidence interval to estimate the population proportion with...
Determine the margin of error for a 99% confidence interval to
estimate the population proportion with a sample proportion equal
to 0.80 for the following sample sizes.
a. n=100 b. n=200 c. n=260
What is the margin of error for the population mean at 90% confidence level for the...
What is the margin of error for the population mean at 90%
confidence level for the information in Data.
Data:
5.1
10.8
6.2
4.3
5.7
7.3
4.7
7.5
8.7
5.5
8.7
7.7
6.5
6.2
11.4
8.1
5.5
12.3
6.4
7.2
7.6
9.2
8.9
6.9
4.8
9.4
11.7
5.6
7.1
13.4
a) 0.74
b) 0.73
c) 0.72
d) 0.75
e) none of the above
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