What is the margin of error for a 99% CI for a mean, when the sample...

What is the margin of error for a 99% CI for a mean, when the sample size is 8, the sample average is 152, the sample std dev is 30, and the sample was drawn from a Normal population? (Enter your answer to two decimals: ex: 12.34).

A 90% confidence interval for the population mean is 30 < mu < 50. What is the sample mean?

A sample of 8 female college students consumes an average of 10 liters of alcohol per month, with a sample standard deviation of 3.9 liters. Monthly alcohol consumption is Normally distributed. What is the margin of error for a 90% Confidence Interval for the mean? (Leave your answer to two decimal places, ex: 18.12)

Solutions

Expert Solution

----------------------------------------------------

Sample mean = (lower+upper)/2 = (30+50)/2 = 40

----------------------------------------------------

orchestra answered 1 year ago

Next > < Previous

Related Solutions

Determine the margin of error for a 99% confidence interval to estimate the population mean when...

Determine the margin of error for a 99% confidence interval to estimate the population mean when s = 43 for the sample sizes below. a) n=12 b) n=25 c) n=46 a) The margin of error for a 99% confidence interval when n=12 is _.

Determine the margin of error for a 99% confidence interval to estimate the population mean when...

Determine the margin of error for a 99% confidence interval to estimate the population mean when s=45 for the sample sizes of n=15, n=34, n=54. (Find the margin of error for each interval when n=x) Determine the margin of error for a confidence interval to estimate the population mean with n=24 and s=12.3 for confidence levels 80%, 90%, 99%.

Find the sample size needed to give, with 99% confidence a margin of error within +/-...

Find the sample size needed to give, with 99% confidence a margin of error within +/- 5 σ = 80 n = ____ σ = 30 n =____ σ =10 n = _____

find the sample size needed to give with 99% confidence a margin of error of plus...

find the sample size needed to give with 99% confidence a margin of error of plus or minus 5% when estimating proportion within plus minus 4% within plus minus 1%

Sigma known Ratings Population Standard Deviation 2.64 Mean 42.95384615 95% CI Margin of Error Standard Error...

Sigma known Ratings Population Standard Deviation 2.64 Mean 42.95384615 95% CI Margin of Error Standard Error 0.327747828 0.641805331 Median 43 95% Confidence Interval Mode 44 42.31204082 43.59565148 Standard Deviation 2.642387469 99% CI Margin of Error Sample Variance 6.982211538 0.843188126 Kurtosis -0.392154755 99% Confidence Interval Skewness -0.446608112 42.11065803 Range 12 43.79703428 Minimum 36 Maximum 48 Sum 2792 Sigma Unknown Count 65 95% Confidence Interval Confidence Level(95.0%) 0.654751556 42.2990946 43.60859771 State the 95% confidence interval for sigma unknown. What is the multiplier...

Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for...

Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for those intervals. Show all work. $32,096 $29,716 $29,227 $27,209 $22,794 $19,306 $19,238 $19,164 18,994 $18,329 $17,978 $17,626 $16,823 $16,709 $15,967 $15,921 $15,908 $15,905 $15,638 $15,629 $14,414 $14,229 $14,137 $14,051 $13,907 $13,776 $13,281 $12,739 $12,300 $11,994 $11,262 $11,112 $10,984 $10,824 $10,823 $10,448 $10,081 $9,883 $9,668 $9,663 $9,337 $8,855 $8,741 $8,596 $8,385 $7,204 $7,072 $6,503 $5,653 $4,602

How large a sample would be needed to form a 99% confidence interval for the mean ticket revenue if desired margin of error is 5 cents?

An inexperienced fair promoter has printed 10,000 tickets for the year Eurelia Solstice fair. There are 5,000 blue tickets for adults, costing $10 each, 3000 green tickets for children, costing $5 each, and 2,000 gold tickets for seniors, costing $4 each. A random sample of 200 Eurelians intending to go to the fair have has been selected by EURELIFAX, the major polling company in Eurelia. in the sample there are a 120 adults, 55 children, and 25 series seniors....

1) margin of error: 0.025; confidence level: 99%; p = .25. The minimum sample size is n...

1) margin of error: 0.025; confidence level: 99%; p = .25. The minimum sample size is n = . 2) margin of error: 0.04; confidence level 98%; p = .7. The minimum sample size is n = . 3) margin of error: 3%; confidence level 95%; p = .5. The minimum sample size is n = . 4) margin of error 2%; confidence level 97%; p = .15. The minimum sample size is n = . 5) margin of error 1.5%; confidence level 96%; p...

What is the margin of error for the population mean at 90% confidence level for the...

What is the margin of error for the population mean at 90% confidence level for the information in Data. Data: 5.1 10.8 6.2 4.3 5.7 7.3 4.7 7.5 8.7 5.5 8.7 7.7 6.5 6.2 11.4 8.1 5.5 12.3 6.4 7.2 7.6 9.2 8.9 6.9 4.8 9.4 11.7 5.6 7.1 13.4 a) 0.74 b) 0.73 c) 0.72 d) 0.75 e) none of the above

Explain the difference between the standard error of a sample proportion and the margin of error...

Explain the difference between the standard error of a sample proportion and the margin of error of a confidence interval for a population proportion.

Subjects