Question

In: Statistics and Probability

Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for...

Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for those intervals. Show all work.

$32,096

$29,716

$29,227

$27,209

$22,794

$19,306

$19,238

$19,164

18,994

$18,329

$17,978

$17,626

$16,823

$16,709

$15,967

$15,921

$15,908

$15,905

$15,638

$15,629

$14,414

$14,229

$14,137

$14,051

$13,907

$13,776

$13,281

$12,739

$12,300

$11,994

$11,262

$11,112

$10,984

$10,824

$10,823

$10,448

$10,081

$9,883

$9,668

$9,663

$9,337

$8,855

$8,741

$8,596

$8,385

$7,204

$7,072

$6,503

$5,653

$4,602

Solutions

Expert Solution

Using Excel's functions for mean( AVERAGE) and standard deviation (STDEV) we have

Mean= 14294 and S.D= 6104.73

The provided sample mean is Xˉ=14294 and the sample standard deviation is s=6104.73. The size of the sample is n=50 and the required confidence level is 80%.

The number of degrees of freedom are df=50−1=49, and the significance level is α=0.2.

Based on the provided information, the critical t-value for α=0.2 and df=49 degrees of freedom is tc =1.299

MARGIN OF ERROR FOR 80% CI

For 95% confidence interval

MARGIN OF ERROR FOR 95% CI

Based on the provided information, the critical t-value for α=0.05 and df=49 degrees of freedom is tc=2.01.

MARGIN OF ERROR=

FOR 99% CONFIDENCE INTERVAL

Based on the provided information, the critical t-value for α=0.01 and df=49 degrees of freedom is tc​=2.68.

MOE


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