In: Statistics and Probability
A random sample of six cars from a particular model year had the following fuel consumption figures ( in miles per gallon). find the 98% confidence interval for the true mean fuel consumption for cars of this model year.
Sample Data: 19.3 , 18.5 , 18.4 , 20.9 , 20.7 , 18.7
Left Endpoint _____
Right Endpoint _____
Let's use Minitab
Here population standard deviation is not given and we have sample data set so we can used one sample t interval to construct the confidence interval for population mean.
Step 1) enter the given data set in minitab columns
Step 2) Stat>>>Basic Statistics >>1 sample t...
Click on "Samples in columns"
select the column name in which your data is present.
then click on Option select level of confidence = 98
Alternative " not equal"
Click on Ok
Again "click on OK"
then we get the following output
From the above output, we get:
Left Endpoint 18.244
Right Endpoint 20.590
One-Sample T: X Mean StDev SE Mean 95% CI 19.417 1.118 0.456 (18.244, 20.590)
Let's use formula :
The formula of t interval is as follows:
+/- E
Where E = margin of error.
Formula of E is as follows:
tc = critical t value
se() is the standard error of sample mean.
Let's use excel for calculation:
The formulae used on the above excel-sheet are as follows: