Question

In: Biology

In a population of 16,000 people, 67 are affected with a mild autosomal recessive condition. What...

In a population of 16,000 people, 67 are affected with a mild autosomal recessive condition. What is the estimated number of carriers for this condition in this population?

Expert Solution

To calculate the estmated number of carriers in the population we have to apply The Hardy- Weinberg equation which is as-

p2 +q2 +2pq=1

where p is the frequency of dominant allele -

q is the frequency of recessive allele -

p2 represents homozygous dominant genotype (autosomal dominant)

q2 represents homozygous recessive genotype - (autosomal recessive)

2 pq represents hetrozygous genotype (carrierof the disease)

As per question we have to calculate the population of the carriers

total number of population is 16000

recessive allele q = 67

q = f(recessive allele)= No of total recessive allele/ Total population

q2 = 67/16000 = 0.0041

The square root of q2 is 0.064

So q = 0.064

p+q =1

p+ 0.064 =1

p = 1- 0.064

p= 0.936

The square of p2 is 0.876

The heterozygous (carrier) population is 2pq

p= 0.936

q= 0.064

2pq= 2* 0.936 * 0.064 = 0.119

So the estimated number of carriers is = 0.119 * 16000 = 1917 approximately

gladiator answered 1 year ago

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