In a population of 16,000 people, 67 are affected with a mild autosomal recessive condition. What...

In a population of 16,000 people, 67 are affected with a mild autosomal recessive condition. What is the estimated number of carriers for this condition in this population?

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Expert Solution

To calculate the estmated number of carriers in the population we have to apply The Hardy- Weinberg equation which is as-

p2 +q2 +2pq=1

where p is the frequency of dominant allele -

q is the frequency of recessive allele -

p2 represents homozygous dominant genotype (autosomal dominant)

q2 represents homozygous recessive genotype - (autosomal recessive)

2 pq represents hetrozygous genotype (carrierof the disease)

As per question we have to calculate the population of the carriers

total number of population is 16000

recessive allele q = 67

q = f(recessive allele)= No of total recessive allele/ Total population

q2 = 67/16000 = 0.0041

The square root of q2 is 0.064

So q = 0.064

p+q =1

p+ 0.064 =1

p = 1- 0.064

p= 0.936

The square of p2 is 0.876

The heterozygous (carrier) population is 2pq

p= 0.936

q= 0.064

2pq= 2* 0.936 * 0.064 = 0.119

So the estimated number of carriers is = 0.119 * 16000 = 1917 approximately

gladiator answered 1 year ago

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