Question

In: Math

The following table compares musical genre preference with preferred leisure activity among Mary's goats. Music: Jazz...

  1. The following table compares musical genre preference with preferred leisure activity among Mary's goats.

Music:

Jazz

Opera

M.R.F.

Kicking Humans

27

32

Reading

35

31

Eating Flowers

41

26

Arson

7

18

Marginal Relative Frequency

  1. Complete a marginal relative frequency distribution above.
  2. What proportion of Mary's goats enjoy peaceful activities (reading, eating flowers)?
  3. Does it seem that musical preference and preferred leisure activity are independent? Justify your answer.

Solutions

Expert Solution

(a) the marginal relative frequency are given as

Music Jazz Opera MRF
Kicking Humans 27/219=0.1244 0.1475 59/217=0.2719
Reading 0.1613 0.1429 0.3041
Eating Flowers 0.1889 0.1198 0.3088
Arson 0.0323 18/219=0.0829 0.1152
Marginal Relative Frequency 110/217=0.5069107/219= 0.4931 1

(b) required proportion =0.3041+0.3088=0.6129

(c) here we use chi-square test with  

null hypothesis H0: musical preference and preferred leisure activity are independent

and alternate hypothesis Ha:musical preference and preferred leisure activity are not independent

test statistic chi-square=sum((O-E)2/E)=8.82 with (r-1)(c-1)=(4-1)(2-1)=3 df

and typical critical chi-square=(0.05,3)=7.81 is less than calculated chi-square=8.82, so we reject the null hypothesis and conclude that :musical preference and preferred leisure activity are not independent

Observed(O) Expected(E) E (O-E) (O-E)2/E
27 110*59/217 29.91 -2.91 0.28
35 110*66/217 33.46 1.54 0.07
41 110*67/217 33.96 7.04 1.46
7 110*25/217 12.67 -5.67 2.54
32 107*59/217 29.09 2.91 0.29
31 107*66/217 32.54 -1.54 0.07
26 107*67/217 33.04 -7.04 1.50
18 107*25/217 12.33 5.67 2.61
217 0 217 0 8.82
critical chi-square(0.05,3)= 7.81

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