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In: Statistics and Probability

Jerome read that in temperate climes, there are more than 133 spiders per square meter of...

Jerome read that in temperate climes, there are more than 133 spiders per square meter of open land with a standard deviation of 4. To test this, he fenced off 31 square meters and carefully counted all the spiders. He found an average of 134.22 spiders per square meter. Which of the following correctly describes the test and hypotheses he should use?

A. A z-test with H0:μ≤133, Ha:μ>133
B. A t-test with H0:μ≥133, Ha:μ<133
C. A t-test with H0:μ≤133, Ha:μ>133
D. A z-test with H0:μ≥133, Ha:μ<133
E. Cannot satisfy normality; do not test

Suppose that Jerome performs the test correctly but that a Type I error occurred. What happened?

A. He found that the average was not greater than 133 when it actually was
B. He found that the average was greater than 133 when it actually was
C. He found that the average was greater than 133 when it actually wasn’t
D. He found that the average was not greater than 133 when it actually wasn’t

Jenny read that the average American house had 992 square feet of room for each inhabitant. To test this, she studied the blueprints of 18 randomly chosen houses in her town. She found an average of 1005.44 with s=38.44. Which of the following correctly describes the test and hypotheses she should use?

A. A z-test with H0:μ=992, Ha:μ≠992
B. A t-test with H0:μ≤992, Ha:μ>992
C. A z-test with H0:μ≤992, Ha:μ>992
D. A t-test with H0:μ=992, Ha:μ≠992
E. Cannot satisfy normality; do not test

A car manufacturer states that the mean mileage for its entire fleet is 29 mpg. Wishing to test this claim, Jane tests 24 randomly chosen cars and finds a mean mileage of 29.76 mpg with a standard deviation of 3.28 mpg. What should she report as the result of her test?

A. Normality not established; do not test
B. Reject the null at the 0.05 level of significance
C. Reject the null at the 0.01 level of significance
D. Fail to reject the null at the 0.05 level of significance

Jada has been told by a breeder that the number of spots on a registered dalmatian dog averages 32 with a standard deviation of 2.63. To test this, she counted the spots on 33 such dogs and found a mean of 32.8. What should she report as the result of her test?

A. Reject the null at the 0.01 level of significance
B. Normality not established; do not test
C. Fail to reject the null at the 0.05 level of significance
D. Reject the null at the 0.05 level of significance

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Expert Solution

orchestra answered 1 year ago
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