In: Statistics and Probability
The average number of mosquitos in a stagnant pond is 80 per square meter with astandard deviation of 12. If 36 square meters are chosen at random for a mosquitocount, find the probability that the average of those counts is more than 81.6 mosquitosper square meter. Assume that the variable is normally distributed.
A)0.3%B)21.2%C)78.8%D)28.8%
Solution :
Given that ,
mean =
= 80
standard deviation =
= 12
=
/
n = 12 /
36 = 2
P(
> 81.6) = 1 - P(
< 81.6 )
= 1 - P[(
-
) /
< (81.6 - 80) /2 ]
= 1 - P(z < 0.8)
= 1 - 0.7881 = 0.2119 = 21.2% , Option B is correct.