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In: Chemistry

4 FeS2(s) + 11 O2(g) → 2 Fe2O3(s) + 8 SO2(g) ΔH = -3307.9 kJ 2...

4 FeS2(s) + 11 O2(g) → 2 Fe2O3(s) + 8 SO2(g) ΔH = -3307.9 kJ

2 H2S(g) + 3 O2(g) → 2 H2O(l) + 2 SO2(g) ΔH = -1125.2 kJ

4 FeO(s) + O2(g) → 2 Fe2O3(s)   ΔH = 578.2 kJ

2 Fe(s) + O2(g) → 2 FeO(s) ΔH = -544 kJ

H2(g) + S(s) → H2S(g) ΔH = -20.2 kJ

2 H2(g) + O2(g) → 2 H2O(l) ΔH = 571.7 kJ

By combining the above equations calculate the ΔH(formation) of FeS2(s).

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queen_honey_blossom answered 1 year ago
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