The bonding in SH4 can be characterized by: Select all that apply Question options: A) polar...

The bonding in SH4 can be characterized by: Select all that apply Question options: A) polar B) nonpolar C) ionic D) electron deficient E) expanded octet F) resonance G) all sigma bonds H) all pi bonds I) a combination of sigma and pi bonds

Expert Solution

The SH4 bond does not exist in reality. It is because H is not an electronegative compaound and hence, does not pull the electrons from the suphur . Therefore, sulfur will be in a negative oxidation state(-4) and this is not possible in a covalent compound as the sulphur atom will then exceed its free shells. This is not favourable.

Hypothetically, This bond would be:- A polar E expanded octet G all sigma bonds. Polar as there is a electronegativity difference between sulphur and hydrogen. Expanded octet as sulphur has more electrons than it should. Sigma bonds are the ones possible as H does not make a Pi bond.

queen_honey_blossom answered 2 years ago

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