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convert vector F = 23.8kN @215 degrees to cartesian form

convert vector F = 23.8kN @215 degrees to cartesian form

Solutions

Expert Solution

it has two components

fx = f cos215 = 23.8 cos215 = -19.49 kN

fy = f sin215 = 23.8 sin 215 = -13.65 KN

F = FXI+FYJ -19.49 KNI-13.65 KNJ

genius_generous answered 1 year ago
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