In: Physics
Expressed in terms of Cartesian unit vectors, a displacement vector has the form: A=(3.00m)i-(4.00m)j where the units are given (meters) Express this vector in polar form
r = sqrt(3^2+4^2) = 5 m
and theta = arctan(-4/3) = -53.13 degree
therefore,
A = 5 <-53.13 degree