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Expressed in terms of Cartesian unit vectors, a displacement vector has the form: A=(3.00m)i-(4.00m)j where the...

Expressed in terms of Cartesian unit vectors, a displacement vector has the form: A=(3.00m)i-(4.00m)j where the units are given (meters) Express this vector in polar form

Solutions

Expert Solution

r = sqrt(3^2+4^2) = 5 m

and theta = arctan(-4/3) = -53.13 degree

therefore,

A = 5 <-53.13 degree


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